I would say courtship, we this is when an animal would be looking for a mate. They would want to make themselves different and bright colors could attract a possible mate for them. I hope this helps!
It's reported inside the riddles or decorations
Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.
- Using the Rydberg formula;
1/λ = RH(1/nf^2 - 1/ni^2)
Given that;
λ = wavelength
RH = Rydberg constant
nf = final state
ni = initial state
- When final state = 3 and initial state = ∞
Then;
1/λ = 1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)
1/λ = 1 × 10^7 m-1 (1/3^2 )
λ = 900 nm
Hence, the correct answer is Paschen, ∞ → 3
Learn more about the Rydberg formula; brainly.com/question/17753747
Ammonium is NH₄⁺ and Carbonate is CO₃⁻² => Ammonium Carbonate is (NH₄)₂CO₃
The proton which is easily abstracted in
1-Benzyl-3-propylbenzene is the proton which is present on carbon atom in between two phenyl rings, or the central carbon which is shared by two benzene rings.
This easy abstraction of proton is due to its high acidity. Remember those species are always more acidic whose
conjugate base is stable. Like the acidity of carboxylic acid is due to stability of the
acetate ion.
In our case the stability of conjugate base arises due to
stability of negative ion due to resonance. As shown below, the negative charge can delocalize on both rings.
I have shown the resonance of negative ion on both Phenyl rings with
Blue and
Pink colors.<span />