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3 years ago

5

A sample of neon gas occuples a volume of 7.5L at 35 °C. If the temperature is increased to 45°C, what is the new volume? (Equat

ion that is helpful: K=
273 + °C)

1 answer:

7nadin3 [17]3 years ago

3 0

Answer:Which of the following statements about the periodic table is true?

Elements in the same column are similar in their properties.

Elements in the same row are similar in their properties.

Elements that start with the same letter are similar in their properties.

Elements that have the same atomic mass are similar in their properties.

Explanation:Which of the following statements about the periodic table is true?

Elements in the same column are similar in their properties.

Elements in the same row are similar in their properties.

Elements that start with the same letter are similar in their properties.

Elements that have the same atomic mass are similar in their properties.

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A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of

Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the <u>reaction</u> between HCl and KOH:

$HCl~+~KOH->~H_2O~+~KCl$

Now <u>for example, we can use a volume of 10 mL of HCl</u>. So, we can calculate the moles using the <u>molarity equation</u>:

$M=\frac{mol}{L}$

We know that $10mL=0.01L$ and we have the concentration of the HCl $0.282M$ , when we plug the values into the equation we got:

$0.282M=\frac{mol}{0.01L}$

$mol=0.282*0.01$

$mol=0.00282$

We can do the same for the KOH values ( $50mL=0.05L$ and $0.141M$ ).

$0.141M=\frac{mol}{0.05L}$

$mol=0.141*0.05$

$mol=0.00705$

So, we have so far <u>0.00282 mol of HCl</u> and <u>0.00705 mol of KOH</u>. If we check the reaction we have a <u>molar ratio 1:1</u>, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an <u>excess of KOH</u>. This excess can be calculated if we <u>substract</u> the amount of moles:

$0.00705-0.00282=0.00423mol~of~KOH$

Now, if we want to calculate the pH value we will need a <u>concentration</u>, in this case KOH is in excess, so we have to calculate the <u>concentration of KOH</u>. For this, we already have the moles of KOH that remains left, now we need the <u>total volume</u>:

$Total~volume=50mL+10mL=60mL$

$60mL=0.06L$

Now we can calculate the concentration:

$M=\frac{0.00423mol}{0.06L}$

$M=0.0705$

Now, we can <u>calculate the pOH</u> (to calculate the pH), so:

$pOH=-Log(0.0705)$

$pOH=1.15$

Now we can <u>calculate the pH value</u>:

$14=~pH~+~pOH$

$pH=14-1.15=12.84$

8 0

3 years ago

If 2.0 liters of oxygen gas react with excess carbon monoxide at 273 K and 1.00 atm, how many liters of carbon dioxide can be pr

vlada-n [284]

The given condition is STP, under this condition, gas has a rule of 22.4 L per mole. And the given equation is already balanced. The ratio of mole number is the same as the ratio of the volume and is also the same as the ratio of coefficients. So the answer is 4.0 liters.

5 0

3 years ago

The attachment below is the question:

irakobra [83]

Answer:

gold

Explanation:

to work out density you do mass which is 38.6 divided by volume which is 2cm cubed and you get the answer of 19.3 so it is gold.

7 0

3 years ago

Which part of the food web is NOT a living thing?

stiks02 [169]

Answer:

the sun

Explanation:

the sun is not alive and plants use photosynthesis to eat the radiation emitted by the sun.

4 0

3 years ago

Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b

mojhsa [17]

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl This elements form an ionic bond, so this option is incorrect.

b.Cl2 Here there are two non metals but the form one single covalent bond, so this option is incorrect.

c.CO2 Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

6 0

3 years ago