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AURORKA [14]
3 years ago
8

If the Ksp of NaCl is experimentally determined to be 53.9, then what is the concentration of Na (in M) when it begins to crysta

llize out of solution
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
4 0

For the concentration of Na in M when it begins to crystallize out of the solution is mathematically given as

Na+ = 0.125M

<h3>what is the concentration of Na in M when it begins to crystallize out of the solution?</h3>

Generally, the equation for the Ksp of the solution is mathematically given as

Na⁺+CL⁻

Ksp = SxS

53.9 = s^2

S = 7.34

Molar mass Nacl 58,44

Solubility = 7.34/58.44

Solubility = 0.125M

In conclusion, the concentration of Na in M when it begins to crystallize out of the solution

Na+ = 0.125M

Read more about Ksp

brainly.com/question/7185695

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3 years ago
100 points! Brainliest if correct!!
Harman [31]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 4 x 2 = 8

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<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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