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AURORKA [14]
3 years ago
8

If the Ksp of NaCl is experimentally determined to be 53.9, then what is the concentration of Na (in M) when it begins to crysta

llize out of solution
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
4 0

For the concentration of Na in M when it begins to crystallize out of the solution is mathematically given as

Na+ = 0.125M

<h3>what is the concentration of Na in M when it begins to crystallize out of the solution?</h3>

Generally, the equation for the Ksp of the solution is mathematically given as

Na⁺+CL⁻

Ksp = SxS

53.9 = s^2

S = 7.34

Molar mass Nacl 58,44

Solubility = 7.34/58.44

Solubility = 0.125M

In conclusion, the concentration of Na in M when it begins to crystallize out of the solution

Na+ = 0.125M

Read more about Ksp

brainly.com/question/7185695

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