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Natali [406]
2 years ago
11

The base of a hexagonal prism has an apothem measuring 10 inches and an area of 346.41 square inches. the prism is 12 inches tal

l. what is the approximate lateral area of the prism? round to the nearest whole number. 139 square inches 416 square inches 693 square inches 831 square inches
Physics
1 answer:
tigry1 [53]2 years ago
8 0

The approximate lateral area of the prism is determined as 831 square inches.

<h3>What is lateral area of the hexagonal prism?</h3>

The lateral area of the hexagonal prism is calculated as follows;

LA = PH

where;

  • P is perimeter of the prism
  • H is height

A = ¹/₂Pa

where;

  • a is apothem = 10 inches
  • A is base area = 346.41 in²

346.41 = ¹/₂(10)P

346.41 = 5P

P = 346.41/5

P = 69.282 inches

LA = PH

LA = 69.282 x 12

LA = 831.38 in²

Learn more about lateral area of prism here: brainly.com/question/296674

#SPJ4

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gregori [183]

The final velocity of the skater is 2.34 m/s forward

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system before and after the ball is thrown must be conserved, in absence of external forces.

Before the ball is thrown, the total momentum is:

p_i = (M+m)u

where

M = 61 kg is the mass of the skater

m = 4.0 kg is the mass of the ball

u = 2.5 m/s (forward) is the combined velocity of the skater and the ball

After, the ball is thrown at twice the velocity, so the final total momentum is

p_f = MV+mv

where

V is the final velocity of the skater

v = 2(2.5) = 5.0 is the final velocity of the ball

Since the total momentum must be conserved, we can write

p_i = p_f\\(M+m)u = MV+mv\\V=\frac{(M+m)u-mv}{M}=\frac{(61+4.0)(2.5)-(4.0)(5.0)}{61}=2.34 m/s

So, the skater is moving at 2.34 m/s (forward) after the shot.

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5 0
3 years ago
A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
Nastasia [14]

Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

v^2=u^2+2as

0^2=14.5^2+2\times a\times 18.25

a=-5.76m/sec^2

We know that acceleration is given by

a=\mu g

5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

6 0
3 years ago
In what way are gravitational and electrical forces similar?
Nadusha1986 [10]

Answer:

D. Both occur between objects independently whether they are in contact  or not.

Explanation:

- The gravitational force is a force that is exerted between two (or more) objects having mass. This force is always attractive and its magnitude is given by

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 are the two masses, and r is the distance between the two masses.

- The electrical force is a force that is exerted between two (or more) objects having electrical charge. It can be either attractive or repulsive, depending on the sign of the two charges, and its magnitude is given by

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 are the two charges, and r the distance between the two charges.

Looking at both formulas, we see that the two forces are present even when the two objects are not in contact with each other (in fact, r can assume any value in the formula). They are said to be non-contact forces. Therefore, the correct option is

D. Both occur between objects independently whether they are in contact  or not.

6 0
3 years ago
A 15-turn circular wire loop with a radius of 3.0 cm is initially in a uniform magnetic field with a strength of 0.5 T. The fiel
lana66690 [7]

To solve this problem it is necessary to apply the definition given in Faraday's law in a solenoid for which it is noted that

\epsilon = - d\frac{\phi_B}{dt}

\epsilon = -NA\frac{dB}{dt}

Where,

N = Number of loops

A = Cross sectional Area

B = Magnetic Field

\epsilon = (15)(\pi(0.03)^2)\frac{0-0.5}{0.1}

\epsilon = 0.212V

\epsilon = 0.21V

Therefore the correct answer is A.

6 0
3 years ago
A ball rolls for 8 seconds and travels 24 meters. How fast was it traveling?
belka [17]

Answer:

The speed of the ball was, v = 3 m/s

Explanation:

Given data,

The time period of the ball, t = 8 s

The distance the ball rolled, d = 24 m

The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,

                              v = d / t      m/s

Substituting the given values in the above equation,

                               v = 24 / 8

                                  = 3 m/s

Hence, the speed of the ball was, v = 3 m/s

8 0
3 years ago
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