If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C
<u>Given the following the details;</u>
- Electric potential = 8 Volts
To find the quantity of charge;
Mathematically, the quantity of charge with respect to electric potential is given by the formula;
![Quantity \; of \; charge = \frac{Energy}{Electric \; potential}](https://tex.z-dn.net/?f=Quantity%20%5C%3B%20of%20%5C%3B%20charge%20%3D%20%5Cfrac%7BEnergy%7D%7BElectric%20%5C%3B%20potential%7D)
Substituting the values into the formula, we have;
![Quantity \; of \; charge = \frac{40}{8}](https://tex.z-dn.net/?f=Quantity%20%5C%3B%20of%20%5C%3B%20charge%20%3D%20%5Cfrac%7B40%7D%7B8%7D)
<em>Quantity of charge = 5 Coulombs</em>
Therefore, the quantity of charge must be <em>5 Coulombs.</em>
Find more information: brainly.com/question/21808222
Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m
Answer:
Tha ball- earth/floor system.
Explanation:
The force acting on the ball is the force of gravity when ignoring air resistance. At the moment the player releases the ball, until it reaches the top of its bounce, the small system for which the momentum is conserved is the ball- floor system. The balls exerts and equal and opposite force on the floor. <u>Here the ball hits the floor, because in any collision the momentum is conserved. Moment of the ball -floor system is conserved</u>. Mutual gravitation bring the ball and floor together in one system. As the ball moves downwards, the earth moves upwards, although with an acceleration on the order of 1025 times smaller than that of the ball. The two objects meet, rebound and separate.
Answer:
The wavelength of the wave is 20 m.
Explanation:
Given that,
Amplitude = 10 cm
Radial frequency ![\omega = 20\pi\ rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%2020%5Cpi%5C%20rad%2Fs)
Bulk modulus = 40 MPa
Density = 1000 kg/m³
We need to calculate the velocity of the wave in the medium
Using formula of velocity
![v=\sqrt{\dfrac{k}{\rho}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7Bk%7D%7B%5Crho%7D%7D)
Put the value into the formula
![v=\sqrt{\dfrac{40\times10^{6}}{10^3}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7B40%5Ctimes10%5E%7B6%7D%7D%7B10%5E3%7D%7D)
![v=200\ m/s](https://tex.z-dn.net/?f=v%3D200%5C%20m%2Fs)
We need to calculate the wavelength
Using formula of wavelength
![\lambda =\dfrac{v}{f}](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cdfrac%7Bv%7D%7Bf%7D)
![\lambda=\dfrac{v\times2\pi}{\omega}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bv%5Ctimes2%5Cpi%7D%7B%5Comega%7D)
Put the value into the formula
![\lambda=\dfrac{200\times2\pi}{20\pi}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B200%5Ctimes2%5Cpi%7D%7B20%5Cpi%7D)
![\lambda=20\ m](https://tex.z-dn.net/?f=%5Clambda%3D20%5C%20m)
Hence, The wavelength of the wave is 20 m.