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3 years ago

When you learned about the Highway Transportation system you learned about 6 different types of people as

Engineering

1 answer:

Musya8 [376]3 years ago

4 0

Answer: 3 different types of people using Highway Transportation system are :

1. Pedestrians - should be given priority while driving.

2. Cyclists - should be given enough space on road.

3. Motorcyclists- should be given enough space on road.

Explanation:

1. Pedestrians - Most of pedestrians use to walk on the footpath along side road that keeps them on a safe side. But there are places without footpath along side road, in that case they have to walk on the road itself. Here, we need to take care for them. We need to wait in case they are crossing road and also check for them while taking a turn.

2. Cyclists - They travel on road but are tough to figure out. They travel at a slower pace compared to cars. To avoid any accident with them, we are supposed to give them enough space which should be equivalent to a car's space.

3. Motorcyclists - They can pass by very closely and also come between lanes. Most of the things to be considered here are same as that of cyclists. Here also, we need to check for them carefully while taking a turn. Also, need to give them enough space.

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(a) Differentiate between heat treatment of ferrous and non-ferrous alloys (b) With your understanding of material's thermal pro

liubo4ka [24]

Answer:

In ferrous metal iron present but on the other hand in the non ferrous material iron does not present.That is why there is a different heat treatment process for ferrous and nonferrous materials.

Ferrous materials contains iron is the main constitute.Like steel ,cast iron ,wrought iron .Steel and cast iron are the alloy element of iron ans carbon.Wrought iron is the purest from of iron.

Heat treatment process for ferrous materials :

1.Normalizing

2.Annealing

3.Quenching

4.Surface hardening

Heat treatment process for non ferrous materials :

Mostly annealing process is used for non ferrous materials.After annealing non ferrous will become soft.

When two metal plates are joined then they form a bimetallic structure.The bimetallic structure is used to find the relationship of thermal temperature and the mechanical displacement.

The use of bimetallic structure -In clock ,thermometers ,engines.

7 0

3 years ago

Which of the following terms describes the path from an electrical source to a switch or plug?

mart [117]

Answer:

transmitter hope thus helped!

Explanation:

8 0

2 years ago

Read 2 more answers

Can you determine the critical distance along a flat surface?

Keith_Richards [23]

Explanation:

Consider a fluid of density, ρ moving with a velocity, U over a flat plate of length, L.

Let the Kinematic viscosity of the fluid be ν.

Let the flow over the fluid be laminar for a distance x from the leading edge.

Now this distance is called the critical distance.

Therefore, for a laminar flow, the critical distance can be defined as the distance from the leading edge of the plate where the Reynolds number is equal to 5 x $10^{5}$

And Reynolds number is a dimensionless number which determines whether a flow is laminar or turbulent.

Mathematically, we can write,

Re = $\frac{\rho .U.x}{\mu }$

or 5 x $10^{5}$ = $\frac{\rho .U.x}{\mu }$ ( for a laminar flow )

Therefore, critical distance

$x=\frac{5\times 10^{5}\times \mu }{\rho \times U}$

So x is defined as the critical distance upto which the flow is laminar.

6 0

2 years ago

Pressurized steam at 400 K flows through a long, thin-walled pipe of 0.6-m diameter. The pipe is enclosed in a concrete (stone m

iris [78.8K]

Answer:

Rate of heat loss per unit length of pipe, q' = 767.01 W/m

Explanation:

Let q' be the Rate of heat loss per unit length

Let q be the Rate of heat loss

q' = q/L

Where L is the length of the pipe

Diameter, D= 0.6m

The rate of heat loss q is given by the formula: q = Sk(T₂ - T₁)

Where k is the thermal conductivity of the concrete at 300 K

k = 1.4 Wb/m-K (at 300K)

And S is the shape factor given by the formula:

S = 2πL/ ln(1.08w/D)

S = (2π*L) / ln(1.08*1.75/0.6))

S = (2π*L) / 1.147

S = 5.48 L

q = 5.48L*1.4(400-300)

q = 767.01 L

q' = q/L

q' = 767.01L/L

q' = 767.01 W/m

4 0

2 years ago

The final position of a car can be predicted with the following equation: Position = -2.5 (time) + 25 Where is the car’s positio

nekit [7.7K]

Answer:

The car's position at 3.0 seconds is 17.5 meters. The car will reach 0.0 meters at 10 seconds.

Explanation:

You can rewrite the equation as P= -2.5t+25. t=time and P is equal to position; so you will plug in 3.0 seconds into t. The equation will now look like: P = -2.5(3.0)+25

P = -2.5(3.0) + 25

P = -7.5 + 25

P = 17.5 meters

Now, to find when the car reaches 0.0 meters, we will plug that into P since P = position and will solve for t.

P = -2.5t + 25

0.0 = -2.5t + 25

-25 -25

-25 = -2.5t

-25/-2.5 = -2.5t/-2.5

10 = t

So the car will reach 0.0 meters at 10 seconds.

8 0

3 years ago