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Answer:
The Debye temperature for aluminum is 375.2361 K
Explanation:
Molecular weight of aluminum=26.98 g/mol
T=15 K
The mathematical equation for the specific heat and the absolute temperature is:

Substituting in the expression of the question:


Here

Replacing:

Answer:
#include<iostream>
Using namespace std;
int main()
{
int n, qty;
double price, amount;
cout<<"Number of items ";
cin>>n;
cout<<"ITEM<<"\t"<<"QUANTITY"<<"\t"<<"PRICE"<<"\t"<<"ITEM TOTAL";
for(int i= 1; I<= n; i++)
{
cin>>qty;
cin>>price;
amount = qty * price;
cout<<i<<"\t "<<qty<<"\t"<<price<<"\t"<<amount;
}
}
Explanation
The above program is written in C++ programming language
5 variables are declared and used in the program
n is declared as an integer to represent the total number of items
qty is declared as integer to represent the total quantity of each item
price is declared as double to represent the amount of each individual item
amount is declared as double to represent the total amount of an item; it is gotten by qty * price
i is declared as integer to iterated between each items
The amount of each item is calculated within the iteration and also printed immediately
Answer:
heat transfer rate is -15.71 kW
Explanation:
given data
Initial pressure = 4 bar
Final pressure = 12 bar
volumetric flow rate = 4 m³ / min
work input to the compressor = 60 kJ per kg
solution
we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is
h1 = 262.96 kJ/kg
v1 = 0.05397 m³/kg
h2 = 310.24 kJ/kg
and here mass balance equation will be
m1 = m2
and mass flow equation is express as
m1 =
.......................1
m1 =
m1 = 1.2353 kg/s
and here energy balance equation is express as
0 = Qcv - Wcv + m × [ ( h1-h2) +
+ g (z1-z2) ] ....................2
so here Qcv will be
Qcv = m × [
] ......................3
put here value and we get
Qcv = 1.2353 × [ {-60}+ (310.24-262.96) ]
Qcv = -15.7130 kW
so here heat transfer rate is -15.71 kW