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Andrew [12]
3 years ago
6

The method of heat transfer that takes place in liquids and gases is? need the answer ASAP!!

Physics
1 answer:
Ratling [72]3 years ago
3 0
The method of heat transfer that takes place in liquids and gases is Convection
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The answer and how to do it
Arturiano [62]
Current = charge per second
2 Coulombs per second = 2 Amperes

Potential difference = (current)x(resistance) in volts.

That's (2 Amperes) x (2 ohms).

That's how to do it.
I think you can find the answer now.
8 0
3 years ago
A wave travels at 330m/s^-1. the wavelength is found to be 2.4m.
sveta [45]

Answer: frequency 137.5

Time period 0.01sec

Explanation:

7 0
2 years ago
Select the correct answer.
11111nata11111 [884]

Answer:

Implicit memory

Explanation:

Implicit memory stores skill-related data by repeating an activity that always follows the same pattern. It includes all motor, sensory, and intellectual skills, as well as every form of conditioning. The capacity thus acquired does not depend on consciousness. We are able to perform sometimes complex tasks with our thinking turned to something completely different. This explains why Adam types so fast without even remembering the exact location of the letters on the keyboard.

8 0
3 years ago
A car moving with an intial velocity of 60m/s is brought to rest in 30 seconds calculate the acceleration
gregori [183]

Answer:

a = 2 [m/s^2]

Explanation:

To solve this problem we must use the expressions of kinematics, we must bear in mind that when a body is at rest its velocity is zero.

v_{f} = v_{i} - (a*t)

where:

Vf = final velocity = 0

Vi = initial velocity = 60 [m/s]

a = desacceleration [m/s^2]

t = time = 30 [s]

Note: the negative sign of the above equation means that the car is slowing down, i.e. its speed decreases.

0 = 60 - (a*30)

a = 2 [m/s^2]

6 0
3 years ago
As a box slides down a ramp, friction does 23.0 joules of work. At the bottom of the ramp, the box has 3.8 joules of kinetic ene
tensa zangetsu [6.8K]

Answer:

The high of the ramp is 2.81[m]

Explanation:

This is a problem where it applies energy conservation, that is part of the potential energy as it descends the block is transformed into kinetic energy.

If the bottom of the ramp is taken as a potential energy reference point, this point will have a potential energy value equal to zero.

We can find the mass of the box using the kinetic energy and the speed of the box at the bottom of the ramp.

E_{k}=0.5*m*v^{2}\\\\where:\\E_{k}=3.8[J]\\v = 2.8[m/s]\\m=\frac{E_{k}}{0.5*v^{2} } \\m=\frac{3.8}{0.5*2.8^{2} } \\m=0.969[kg]

Now applying the energy conservation theorem which tells us that the initial kinetic energy plus the work done and the potential energy is equal to the final kinetic energy of the body, we propose the following equation.

E_{p}+W_{f}=E_{k}\\where:\\E_{p}= potential energy [J]\\W_{f}=23[J]\\E_{k}=3.8[J]\\

And therefore

m*g*h + W_{f}=3.8\\ 0.969*9.81*h - 23= 3.8\\h = \frac{23+3.8}{0.969*9.81}\\ h = 2.81[m]

8 0
3 years ago
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