Question

GIVING BRAINLIST!!!!! Given that the area of rectangle IJKL is 490 units^2, what are its length and width?

Answer 1

Given :

Area of rectangle = 490 units²

length = 8x

width = 5x

As we know

$\:\bf\boxed{{Area\:of\:rectangle\:=\:length\:}x\:{width}}$

So,

Area of rectangle = l x w

=> 490 units² = $\:\mathsf{8x\: x\: 5x}$

=> 490 = $\:\mathsf{40x²}$

=> $\:\mathsf{\frac{490}{40}}$ = x²

=> x² = $\:\mathsf{\frac{49}{4}}$

=> x = $\:\mathsf{\sqrt{\frac{49}{4}}}$

=> x = $\:\mathsf{\frac{7}{2}}$

=> x = $\:\mathsf{3.5}$

Now,

length = 8x = 8 x 3.5 = 28 units

width = 5x = 5 x 3.5 = 17.5 units

Therefore the required length and width of the rectangle are 28 units and 17.5 units.

Hope this helps!

Answer 2

Answer:

See below ~

Step-by-step explanation:

Given

1. Area = 490 units²
2. Width = 5x
3. Length = 8x

Now, we know that : length x width = area

Using the given values

• (8x)(5x) = 490
• 40x² = 490
• x² = 490/40
• x² = 49/4
• x = √49/4
• x = 7/2 = 3.5

Length (l) = 8x = 8(3.5) = 28 units

Width (w) = 5x = 5(3.5) = 17.5 units