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andrezito [222]
2 years ago
8

What is the velocity of the person walking below?

Physics
1 answer:
posledela2 years ago
5 0

Answer:

2

Explanation:

We would use the formula for velocity!

V= displacement/time

Displacement would be how far the person walked

Time would be the time on the side

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Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg
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Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg elephant. They are separated by 8

4 0
3 years ago
A toy floats in a swimming pool. The buoyant force exerted on the toy depends on the volume ofa. none of these choices.b. all th
Citrus2011 [14]

Answer:c

Explanation:

The buoyancy force on toy depends upon the volume of toy under pool water.

According to Archimedes principle buoyant force on a floating body depends upon the weight of displaced liquid by object.

Buoyancy force is given by

F_b=\rho _f\times V\times g

where \rho _f=density of fluid

V=volume of object under water

g=acceleration due to gravity

6 0
4 years ago
What term is used to denote the change of velocity with time
Westkost [7]
The answers is acceleration.
6 0
3 years ago
Read 2 more answers
Find the electric field at a point midway between two charges of +40.0 x 10^-9 c and.+60.0 x 10^-9 c
PIT_PIT [208]
Missing part in the text: "...the charges are <span>separated by a distance of 30.0 cm."
</span>
Solution:
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
E=k_e \frac{q}{r^2}
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).

Let's calculate the electric field generated by the first charge:
E_1 = (8.99 \cdot 10^9 Nm^2 C^{-2} ) \frac{+40.0 \cdot 10^{-9} C}{(0.15 m)^2}=1.6 \cdot 10^4 N/C

While the electric field generated by the second charge is
E_2 = (8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{+60.0 \cdot 10^{-9} C}{(0.15 m)^2}=2.4 \cdot 10^4 N/C

Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
E=E_2 - E_1 = 2.4 \cdot 10^4 N/C - 1.6 \cdot 10^4 N/C = 8000 N/C
4 0
3 years ago
Lien uses a spring scale to pull a block toward the right across the lab table. The scale reads 8 N. Which force should Lien con
lana66690 [7]

Answer:

<h2>Frictional force</h2>

Explanation:

For the block placed on the table, there are several force acting on the body along the horizontal and vertical axis. All this forces tends to keep the body in a state of equilibrium.The forces acting along the horizontal are the moving force (Fm) and the frictional force (Ff).

Frictional force are forces that acts opposite to the force that causes the body to move (moving force).

If Lien uses a spring scale to pull a block toward the right across the lab table and the scale reads 8 N, this means that the force that causes the body to move is the 8N force (moving force).

Taking the sum of force along the horizontal;

\sum fx = ma_x

Since the body is static, max = 0

\sum fx = 0\\fm+(-Ff)= 0

Note that the frictional force acts is the force of opposition acting in the negative x direction.

fm = 0+Ff\\fm = Ff

Since Fm = 8N, Ff will also be equal to 8N.

Based on the above proof, Lien can also conclude that 8 N is a frictional force

6 0
3 years ago
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