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jonny [76]
3 years ago
8

Can someone please help me with these three questions, it will soon be due.

Chemistry
1 answer:
Mice21 [21]3 years ago
8 0

YOU also better mark me BRAINLIEST if someone else answers!!!

1)

volume = 100 mL

density = 1.02 g / mL

mass = density x volume

  • = 1.02 x 100
  • = 102 g
  1. Cp = 4.03 J / oc g
  2. dT = 28.7 - 23.5 = 5.2 oC
  3. Q = m Cp dT
  4. Q = 102 x 4.03 x 5.2
  5. Q = 2138 J
  6. Q = 2.14 kJ

heat absorbed = 2.14 kJ

2)

  • We can calculate the moles of HC1 present in 50 ml 1m solution by using the formula, moles = volume of solution  in L*molarity
  • moles = 50/1000 = .05 , L*1 M = .05 Moles of HCL.
  • The same can be applied for calculation  of moles fo  Na OH of 50 ml, 1 M solution. (50 ml NaOH = .o5 L NaOH)
  • Then use the formula = volume of solution / 1000*moles.wt,
  • =1.825 gram.
  • moles=mass in grams /moles.wt= .05 moles of HCI
  • calculate moles of water from this reaction.
  • HC1+NaOH----->NACl+h20 (Balanced Equation)
  • .5+.5----> .5+.5
  • .05 moles of water
  • Delta H=q/n.
  • n=.05 to calculate the Delat H.

3) I don't understand it, sorry


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When Brian first sorted out his thoughts, he figured this was the first day after the crash and what did he think would happen n
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Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a
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Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100   ..........(1)

The formula used for relative humidity is:

\text{Relative humidity}=\frac{p_v}{p^o_v}       ...........(2)

where,

p_v = partial pressure of water vapor

p^o_v = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

p=750mmHg

p^o_v=17.5mmHg

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

0.80=\frac{p_v}{17.5mmHg}

p_v=14mmHg

Now we have to calculate the percent humidity by using equation 1.

\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100

\text{Percent humidity}=79.62\%

Therefore, the percent humidity is 79.62 %

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A sample of nitrogen occupies 10.0 liters at 25°C and 98.7 kPa. What would be the volume at 20°C and 102.7 kPa?
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To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.

n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
n = 0.40 mol N2

At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:

V = nRT / P
V = 0.40 x 8.314 x 293.15 / 102.7 x 10^3
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Then we all die because the sun would blow up the earth.
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