Question

Can someone please help me with these three questions, it will soon be due.

Answer 1

YOU also better mark me BRAINLIEST if someone else answers!!!

1)

volume = 100 mL

density = 1.02 g / mL

mass = density x volume

• = 1.02 x 100
• = 102 g

1. Cp = 4.03 J / oc g
2. dT = 28.7 - 23.5 = 5.2 oC
3. Q = m Cp dT
4. Q = 102 x 4.03 x 5.2
5. Q = 2138 J
6. Q = 2.14 kJ

heat absorbed = 2.14 kJ

2)

• We can calculate the moles of HC1 present in 50 ml 1m solution by using the formula, moles = volume of solution  in L*molarity
• moles = 50/1000 = .05 , L*1 M = .05 Moles of HCL.
• The same can be applied for calculation  of moles fo  Na OH of 50 ml, 1 M solution. (50 ml NaOH = .o5 L NaOH)
• Then use the formula = volume of solution / 1000*moles.wt,
• =1.825 gram.
• moles=mass in grams /moles.wt= .05 moles of HCI
• calculate moles of water from this reaction.
• HC1+NaOH----->NACl+h20 (Balanced Equation)
• .5+.5----> .5+.5
• .05 moles of water
• Delta H=q/n.
• n=.05 to calculate the Delat H.

3) I don't understand it, sorry