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3 years ago

What us the problem to 5^4×3^2

Mathematics

2 answers:

rjkz [21]3 years ago

7 0

Answer:

5625

Step-by-step explanation:

First simplify 5^ 4 and 3^2

5 x 5 x 5 x 5 = 625

3 x 3 = 9

Now you have to multiply the two numbers together.

625 x 9 = 5625

torisob [31]3 years ago

4 0

Answer:

The answer is 5625

Step-by-step explanation:

Lets break up the problem

So you have two things: 5^4 and 3^2

Solve seperately

Gives you 625 and 9

Then multiply both together

625*9 = 5625

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0= - z/3 + 4 Can you help me?

scoundrel [369]

Answer:

z=12

Step-by-step explanation:

subtract both sides by 4:

-z/3=-4

then multiply both sides by -3:

z=12

6 0

2 years ago

Read 2 more answers

Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

8 0

11 months ago

Solve the following inequality: –1 + 6(–1 – 3x) > –39 – 2x.

insens350 [35]

–1 + 6(–1 – 3x) > –39 – 2x.
-1-6-18x>-39-2x
-7-18x>-39-2x
-18x>-32-2x
-16x>-32
x<2

B. x<2

7 0

3 years ago

Read 2 more answers

Are all rational equation solutions valid?

Semenov [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

A shoe store uses a 38% markup to price their items. The store buys the

Lorico [155]

Answer:

They will Markup the price by $19.76.

Step-by-step explanation:

Markup percent = 38%

Wholesale Price = $52

Markup price can be calculated by simply multiplying the wholesale price by 38% or 0.38.

Markup price = 38% of 52

= 38/100 × 52

= 0.38 × 52

= $19.76

Therefore, they will Markup the price by $19.76.

8 0

2 years ago