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Furkat [3]
3 years ago
9

What us the problem to 5^4×3^2

Mathematics
2 answers:
rjkz [21]3 years ago
7 0

Answer:

5625

Step-by-step explanation:

First simplify 5^ 4 and 3^2

5 x 5 x 5 x 5 = 625

3 x 3 = 9

Now you have to multiply the two numbers together.

625 x 9 = 5625

torisob [31]3 years ago
4 0

Answer:

The answer is <u>5625</u>

Step-by-step explanation:

Lets break up the problem

So you have two things: 5^4 and 3^2

Solve seperately

Gives you 625 and 9

Then multiply both together

625*9 = <u>5625</u>

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If y-18=14 what is the value of 3(y+5)?
svlad2 [7]
y-18=14\ \ \ /+18\\\\y-18+18=14+18\\\\y=32\\\\substitute\ to\ 3(y+5):\\\\3\cdot(32+5)=3\cdot37=111
4 0
3 years ago
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
4 years ago
divide the number 120 into three parts such that the first and second are twice and three times the third respectively HELP MEEE
Misha Larkins [42]

Answer:

Step-by-step explanation:

Step by step:

8 0
3 years ago
Can anybody help? Having a little trouble with this during quarantine...
kolbaska11 [484]
First you would have to find the base which would be 9^2 + 9^2= C^2 because of the pythagorean theorem. So the base would equal 12.7. To find the area of a triangle it’s A= h•b / 2. So your answer would be 95.25
6 0
3 years ago
A circle has a diameter of
nignag [31]

Answer:

Circumference = 50.24 units

Area = 200.96 units²

Determining the area of the circle:

The formula of finding the area of the circle is π(r)² or π(d/2)².

(Where "r" represents the radius and "d" represents the diameter)

In this case, we are given the diameter. Thus, we will use the formula π(d/2)². Simply substitute the diameter in the formula to determine the area of the circle.

⇒ π(D/2)² = Area of circle

⇒ π(16/2)² = Area of circle

⇒ π(8)² = Area of circle

⇒ π × 64 = Area of circle

[Exact form of pie: 22/7; Approx form of pie: 3.14]

⇒ Area of circle ≈ 3.14 × 64

⇒ Area of circle ≈ 200.96 units²

Determining the circumference of the circle:

The formula of finding the circumference of a circle is 2πr or πd.

(Where "r" is radius and "d" is diameter)

In this case, we are given the diameter. Thus, we will use the formula πd. Simply substitute the diameter in the formula to determine the circumference of the circle.

⇒ πd = Circumference of circle

⇒ π(16) = Circumference of circle

[Exact form of pie: 22/7; Approx form of pie: 3.14]

⇒ (3.14)(16) ≈ Circumference of circle

⇒ 50.24 units ≈ Circumference of circle

4 0
2 years ago
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