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Luba_88 [7]
2 years ago
8

5. Students hypothesize that temperature is a limiting factor for the germination of seeds. They carry out an experiment to

Chemistry
1 answer:
Lelechka [254]2 years ago
8 0

Answer:

keep adding to on each term its quit simple

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Compute the following and give your answer on scientific notation
Nata [24]

Answer:

6*10^-3

Hope it helps

Procedure in the attached file

4 0
3 years ago
Calculate the number of moles in a 2.98 g sample of aluminum.
Ksju [112]
Molar mass <span>Aluminium ( Al) = 26.98 g/mol

1 mole ------------ 26.98 g
? mole ----------- 2.98 g

moles Al = 2.98 x 1 / 26.98

moles Al = 2.98 / 26.98

= 0.110 moles

hope this helps!

</span>
3 0
3 years ago
Explain the Law of Conservation of Energy!
kaheart [24]
<span>In physics, the law of conservation of energy states that the total energy of an isolated system remains constant—it is said to be conserved over time. Energy can neither be created nor destroyed; rather, it transforms from one form to another.</span>
5 0
3 years ago
Read 2 more answers
if a solution is saturated, how does the rate of dissolution of a solute compare with it's rate of crystallization?
LenKa [72]

Answer:

The same

Explanation:

In a saturated solution, the rate of dissolution is equal and the same to the rate of crystallization.

  • A saturated solution of as substance (solute) at a particular temperature is one which contains the maximum amount of the substance that can dissolve at that temperature  in the presence of the crystals of the substance.
  • It is an equilibrium system in which a solid substance is in equilibrium with its own ions in solution.
  • Therefore the rate of dissolution will the same with that of crystallization.
8 0
3 years ago
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i
alexdok [17]

Answer:

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

Explanation:

The pH of the solution = 2.46

pH=-\log[H^+]

2.46=-\log[H^+]

[H^+]=0.003467 M

HA\rightleftharpoons H^++A^-

Initially

0.0144         0      0

At equilibrium

(0.0144-x)       x       x

The expression if an dissociation constant is given by :

K_a=\frac{[A^-][H^+]}{[HA]}

K_a=\frac{x\times x}{(0.0144-x)}

x=[H^+]=0.003467 M

K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}

K_a=1.099\times 10^{-3}

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

3 0
3 years ago
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