Why is Darwin criticized for his theory? and who were they

2 answers:

4 0

A few people criticized Darwin for his theory, such as the left-leaning biologists Stephen Jay Gould and Richard Lewontin, who fear the political implications of Darwinian theory. They fear that evolutionary theory, even when bolstered by modern genetics, and molecular biology, does not make reality probable enough.

Amiraneli [1.4K]2 years ago

4 0

Answer:

When Charles Darwin published his 1859 book On the Origin of Species, he convinced most of the scientific community that new species arise through descent through modification in a branching pattern of divergence from common ancestors, but while most scientists accepted natural selection as a valid and empirically ...

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What process occurs when all of the energy from light waves is transferred to a medium?

Wittaler [7]

Absorption happens when <span>all of the energy from light waves is transferred to a medium.</span>

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3 years ago

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3 years ago

susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o

prisoha [69]

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3600joules

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2 years ago

A closed cylinder with a 0.15-m radius ends is in a uniform electric field of 300 n/c, perpendicular to the ends. the total flux

bixtya [17]

The total flux through the cylinder is zero.

In fact, the electric flux through a surface (for a uniform electric field) is given by:

$\Phi = E A \cos \theta$

where

E is the intensity of the electric field

A is the surface

$\theta$ is the angle between the direction of E and the perpendicular to the surface, whose direction is always outwards of the surface.

We can ignore the lateral surface of the cylinder, since the electric field is parallel to it, therefore the flux through the lateral surface of the cylinder is zero (because $\theta=90^{\circ}$ and $\cos \theta=0$ ).

On the other two surfaces, the flux is equal and with opposite sign. In fact, on the first surface the flux will be

$\Phi_1 = E \pi r^2$

where r is the radius, and where we have taken $\theta=0^{\circ}$ since the perpendicular to the surface is parallel to the direction of the electric field, so $\cos \theta=1$ . On the second surface, however, the perpendicular to the surface is opposite to the electric field, so $\theta=180^{\circ}$ and $\cos \theta=-1$ , therefore the flux is