Answer:
<em>Elevator That Is Moving Downwards At A Constant Speed Of 4.9 M/S. What Is The Magnitude Of The Net Force Acing On The Student?</em>
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<em>This problem has been solved!See the answerA student weighs 1200N. They are standing in an elevator that is moving downwards at a constant speed of </em><em>4.9 m/s. What is the magnitude of the net force acing on the student?</em>
Answer:
322.6 m/s
Explanation:
Given that there are two components of position;
x= vot
y component is;
y= 1.9 - gt^2/2
When the bullet hits the ground, y=0
1.9 -gt^2/2 =0
Where g = 10ms^-2
t= √2 × 1.9/10
t= 0.62 secs
Therefore,
x= vot
vo = x/t
Where, x= 200 m
vo= 200/0.62 =
vo= 322.6 m/s
The acceleration of the car is determined as 0.626 m/s².
<h3>
What is acceleration?</h3>
The acceleration of an object is the change in velocity of the object with time.
a = Δv/t
where;
- Δv is change in velocity
- t is the time of motion
Substitute the given parameters and solve for the acceleration.
v = 14 mph = 6.258 m/s
a = (6.258 m/s) / (10 s)
a = 0.626 m/s²
Thus, the acceleration of the car is determined as 0.626 m/s².
Learn more about acceleration here: brainly.com/question/14344386
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