Convert 19 kcal into joules

ICMP scanning involves in checking for the live systems, which can be done by sending the following ping scan request to a host.

abruzzese [7]

Answer:

ICMP Echo Request

Explanation:

ICMP Echo Request is a form of probe or message sent by a user to a destination system.

5 0

3 years ago

Why would defective collagen proteins affect an individuals joints?

umka21 [38]

Answer:

Defective collagen proteins affect an individuals joints, as collagen is an important component protein in body connective tissues

Explanation:

Collagen is a crucial protein in the extracellular matrix of various connective tissues in body (tendons, ligaments, muscles). It constitutes major protein component in mammals body.

Collagen Vascular disease is a group of diseases affecting 'collagen' connecting tissue. Apart from inheritance, they can con occur due to autoimmune disease. This implies that body's immune system fights against itself & mistakenly damages its own tissues. So, these diseases have a huge bearing on body joints components. Eg : Lupus , Arthritis are common collagen vascular diseases. Arthritis mostly affects adults above 30 years of age, lupus can be diagnosed in younger people above 15 years of age also.

6 0

2 years ago

What is the percent composition by mass of each element in Co(HSO4)2?

MrRissso [65]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

2 moles of O therefore 32g are O

2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

(40.08 / 74.08) . 100 = 54.1 %

(32 / 74.08) . 100 = 43.2 %

(2 / 74.08) . 100 = 2.7%

im a smart one

7 0

2 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

Answer: The mass of HCl present in 500 mL of acid solution is 36.5 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0

2 years ago

Assuming that a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, determine how many kg of co2 are prod

sleet_krkn [62]

Answer: -

If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

Explanation: -

Density of the gasoline = 0.77 kg / liter

Volume of the tank containing the gasoline = 80 liter.

Mass of gasoline produced from each tank

= Volume of the tank containing the gasoline x Density of the gasoline

= $\frac{0.77 kg}{1 liter}$ x 80 liter

= 61.6 kg

Chemical formula of gasoline = C₈H₁₈

Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol

Number of moles of C₈H₁₈ = $\frac{61.6 g}{114 g}$ x 1 mol

= 0.54 mol of C₈H₁₈

The chemical equation for the burning of gasoline is

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

From the balanced equation we see

2 mol of C₈H₁₈ gives 16 mol of CO₂

0.54 mol of C₈H₁₈ gives $\frac{16 mol CO2 x 0.54 mol C8H18}{2 mol C8H18}$ mol of CO₂

= 4.32 mol of CO₂

Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol

Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂

= $\frac{60g x 4.32 mol}{1 mol}$

= 259.2 g

= $\frac{259.2}{1000}$

= 0.259 Kg

= 0.26 kg rounded off to 2 significant figures.

Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

4 0

2 years ago