For, ClO3- there are 26 valence electrons, so total pairs of electrons are 13.
3A (also known as group 13) all the elements have 3 electrons in their outer most shell thats why theyll be divided into the ns2 and the np1
The answer would look something like this. (sorry for the ugliest diagram ever.)
Explanation:
NH₄F+ AICI₃, → NH₄CI + AlF₃
NH,F: in ionic form
NH₄⁺ + F⁻ = NH₄F
AICI in ionic form:
Al³⁺ + Cl⁻ = AlCl₃
NH Cl in ionic form:
NH₄⁺ + Cl⁻ = NH₄Cl
Al F in ionic form:
Al³⁺ + F⁻ = AlF₃
NH₄F+ AICI₃, → NH₄CI + AlF₃
Now we have to balance the equation with respect to the atoms:
aNH₄F+ bAICI₃, → cNH₄CI + dAlF₃
for N: a = c
H: 4a = 4c
F: a = 3d
Cl: 3b = c
let a = 1
c = 1
b = 
d =
Therefore we can imply that:
a = 3, b = 1 , c = 3 and d = 1 if we multiply through by 3
3NH₄F+ AICI₃, → 3NH₄CI + AlF₃
Learn more:
Chemical equation brainly.com/question/2924195
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HISTORICAL INTRODUCTION.1<span> EVER since the establishment of the atomic theory by Dalton and Berzelius it was felt among chemists that there must be some relation between the atomic weights of the different elements and their properties. It was recognized very early that there exist groups of elements possessing related chemical and physical properties, and one of the earliest attempts to bring out this point is due to Dobereiner. In 1829 he tried to show that “many elements may be arranged in groups ()f three, in each of which the middle element has an atomic weight equal or approximately equal to the mean of the atomic weights of the two extremes.” As illustrations of this method of arrangement may be mentioned the following groups: Li, Na, K; Ca,Sr,</span>
