Question

1.

Answer 1

Answer: The value of $K_p$ is 324

Explanation:

We are given:

Initial pressure of $S_8(g)$ = 1.00 atm

The chemical equation for the conversion of $S_8(g)$ to $S_2(g)$ follows:

                  $S_8(g)\rightleftharpoons 4S_2(g)$

Initial:          1

At eqllm:    1-x       4x

We are given:

Equilibrium partial pressure of $S_8(g)=0.25atm$

Evaluating the value of 'x', we get:

$\Rightarrow (1-x)=0.25\\\\\Rightarrow x=1-0.25=0.75$

The expression of $K_p$ for the above reaction follows:

$K_p=\frac{(p_{S_2})^4}{p_{S_8}}$

$p_{S_2}=4x=(4\times 0.75)=3atm$

$p_{S_8}=0.25atm$

Putting values in above expression, we get:

$K_p=\frac{3^4}{0.25}\\\\K_p=324$

Hence, the value of $K_p$ is 324