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Fofino [41]
2 years ago
15

Select two things that environmental engineers concentrate on during green projects.

Engineering
1 answer:
Elena L [17]2 years ago
3 0

Two things that environmental engineers concentrate on during green projects are fossil fuels and natural resources.

<h3 /><h3>What does environmental engineer do?</h3>

Environmental engineers are responsible for ensuring that there is little or no effect on the environment as a result of human activities.

Hence, two things that environmental engineers concentrate on during green projects are fossil fuels and natural resources.

Learn more about environmental engineer here : brainly.com/question/1322350

#SPJ1

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_______is defined as the use of statistical techniques to control a process or production method
Wittaler [7]

Answer:

Statistical process control

Explanation:

The answer for the given blank is "Statistical process control".

The Statistical process control is the method that is applied by the employs to control the quality of the process and also, to monitor and control the process.

The Statistical process control helps in ensuring the efficiency of the process and ensuring the waste production is less.

8 0
4 years ago
50POINTS
maxonik [38]

Answer:

Ensure that all material and energy inputs and outputs are as inherently safe and benign as possible. Minimize the depletion of natural resources. Prevent waste. Develop and apply engineering solutions while being cognizant of local geography, aspirations, and cultures.Green engineering is the design, commercialization, and use of processes and products that minimize pollution, promote sustainability, and protect human health without sacrificing economic viability and efficiency.The goal of environmental engineering is to ensure that societal development and the use of water, land and air resources are sustainable. This goal is achieved by managing these resources so that environmental pollution and degradation is minimized.

Explanation:i helped

7 0
3 years ago
Read 2 more answers
The Reynolds number is the major parameter that relates fluid flow momentum to friction forces. How is the Reynolds number defin
fiasKO [112]

Answer:

Reynolds number determines whether a flow is laminar or turbulent flow.

Explanation:

Reynolds number is defined as ratio of inertia force to the viscous force. it is a dimension less  number. Reynolds number is used to describe the type of flow in a fluid whether it is laminar flow or turbulent flow. Reynolds number is denoted by Re.

When Reynolds number is in the range of 0 to 2000, the flow is considered to be laminar.

When Reynolds number is in the range of 2000 to 4000, the flow is considered to be transition.

And when Reynolds number is more than 4000, the flow is turbulent flow.

                     The boundary layer thickness for a fluid is given by

                                      δ = \frac{5\times x}{\sqrt{Re}}

where δ is boundary layer thickness

           x is distance from the leading edge

           Re is Reynolds number

Thus from the above boundary layer thickness equation, we can see that the boundary layer thickness varies inversely to square root of reynolds number.

8 0
3 years ago
Give me an A please!!!¡!!!!¡
Andrei [34K]

Answer:

I am in 6th grade why am i in high school things.

Explanation:

8 0
3 years ago
A gas turbine has a thermal efficiency of 20% and develops a power output of 8 MW. Determine the fuel consumption rate if heatin
AlexFokin [52]

Answer:

0.8 kilograms of fuel are consumed each second.

Explanation:

As turbines are steady-state devices, the thermal efficiency of a turbine is equal to the percentage of the ratio of the output power to fluid power, that is:

\eta_{th} = \frac{\dot W}{\dot E} \times 100\,\%

The fluid power is:

\dot E = \frac{\dot W}{\eta} \times 100\,\%

\dot E = \frac{8\,MW}{20\,\%}\times 100\,\%

\dot E = 40\,MW

Which means that gas turbine consumes 40 megajoules of fluid energy each second, which is heated and pressurized with help of the fuel, whose amount of consumption per second is:

50\,\frac{MJ}{kg} = \frac{40\,MJ}{m_{fuel}}

m_{fuel} = 0.8\,kg

0.8 kilograms of fuel are consumed each second.

3 0
3 years ago
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