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Kipish [7]
2 years ago
14

If 100g of an isotope undergoes two half-lives, how many grams will be remaining?

Physics
1 answer:
katrin [286]2 years ago
6 0

C. 25 grams

Explanation:

100g l 0 half-lives

50g l 1 half-life

25g l 2 half-lives

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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
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Answer:

E1  = 10.15 * 10^4 N/C

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Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

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distance between thin glass rods   = 4 cm .

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electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

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2 years ago
What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds​
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gravitational force

...........

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