2 years ago

If 100g of an isotope undergoes two half-lives, how many grams will be remaining?

Physics

1 answer:

katrin [286]2 years ago

6 0

C. 25 grams

Explanation:

100g l 0 half-lives

50g l 1 half-life

25g l 2 half-lives

You might be interested in

A gas at a pressure of 2.10 atm undergoes a quasi static isobaric expansion from 3.70 to 5.40 L. How much work is done by the ga

BartSMP [9]

Answer:

Total work done in expansion will be $3.60\times 10^5J$

Explanation:

We have given pressure P = 2.10 atm

We know that 1 atm $=1.01\times 10^5Pa$

So 2.10 atm $=2.10\times 1.01\times 10^5=2.121\times 10^5Pa$

Volume is increases from 3370 liter to 5.40 liter

So initial volume $V_1=3.70liter$

And final volume $V_2=5.40liter$

So change in volume $dV=5.40-3.70=1.70liter$

For isobaric process work done is equal to $W=PdV=2.121\times 10^5\times 1.70=3.60\times 10^5J$

So total work done in expansion will be $3.60\times 10^5J$

5 0

2 years ago

Q5- Knowing now that your mood might affect your memory, what strategies could you employ to assist your memories and make sure

Tema [17]

You can try recalling and rehearsing information about the memory.

4 0

1 year ago

A crucial characteristic of turbines in tidal generators is that _____.

Mila [183]

<span>The blades should turn in two directions.</span>

4 0

2 years ago

Read 2 more answers

A car accelerates from rest to a speed of 8 m/s over a distance of 16 m. What is the acceleration of the car?

Marina CMI [18]

B because all you do is divide 16 and 8 to find your answer

5 0

3 years ago

Read 2 more answers

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

irina [24]

Explanation:

The charge on the electron is, $q=-1.6\times 10^{-19}\ C$

The electric field at a distance r from the electron is :

$E=k\dfrac{q}{r^2}$

Where

k is the electrostatic constant, $k=\dfrac{1}{4\pi \epsilon_o}$

We know that the electric field lines starts from positive charge and ends at the negative charge. Also, for a positive charge the field lines are outwards while for a negative charge the field lines are inwards.

So, the correct option is " the electric field is directed toward the electron and has a magnitude of $k\dfrac{q}{r^2}$ . Hence, this is the required solution.

4 0

2 years ago