Answer:

Explanation:
From the question we are told that
The distance of the screen is 
The distance of separation of the slit is 
The wavelength of light is 
Generally the condition for constructive interference is

=> ![\theta = sin^{-1} [ \frac{ n * \lambda }{d } ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B%20n%20%2A%20%20%5Clambda%20%7D%7Bd%20%7D%20%5D)
here n = 1 because we are considering the central diffraction peak
=> ![\theta = sin^{-1} [ \frac{ 1 * 588*10^{-9} }{0.0328*10^{-3} } ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B%201%20%2A%20%20588%2A10%5E%7B-9%7D%20%7D%7B0.0328%2A10%5E%7B-3%7D%20%7D%20%5D)
=> 
Generally the width of central diffraction peak on a screen is mathematically evaluated as

substituting values


A) turning
b)greater
c) greater
d) force*distance
e)Nm
Answer:
if i am not mistaken the volume is 7, because it only took that much space
Answer: Height of building = 17.69m, velocity of brick = 18.6m/s
Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.
By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of
.
Time taken to fall = 1.90s
a)
thus the height of the building is calculated using the formulae below

but u = 0 , hence


b)
to get the value of velocity (v) as the brick hits the ground, we use the formulae below

but u= 0, hence


find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph