How is the precision of a calculated result related to the precision of the measurement used in the calculation?
1 answer:
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Answer:
hydrogen=161mmHg
Explanation:
<h3>Answer:</h3>
Bonding Pair Electrons = 2
Lone Pair of Electrons = Zero
<h3>Explanation:</h3>In order to answer this question one should draw the Lewis structure of Fluoramine first following following steps.
Step 1:
First of all add all the valence electrons present in all elements of the given compound. i.e.
Hydrogen × 2 = 1 × 2 = 2
Fluorine × 1 = 7 × 1 = 7
Nitrogen × 1 = 5 × 1 = 5
Total Valence Electrons = 14
Step 2:
Draw the central atom (i.e. Nitrogen) and surround it by remaining elements. In our case Nitrogen is surrounded by two H atoms and one F atom.
H N H
F
Step 3:
Connect all atoms to central atom via a single bond and subtract 2 electrons per bond from total valence electrons. As there are three single bonds so, we will subtract 6 electrons from 14 valence electrons and are left with 8 valence electrons. Now, these remaining 8 electrons are distributed among the elements starting from most electronegative (i.e. Fluorine) and then Nitrogen. So, Fluorine will get 3 lone pair of electrons and \nitrogen will get one lone pair of electrons as shown in figure.
<h3>Conclusion:</h3>As Hydrogen atoms are making only single bonds hence, they will have two bonding pair electrons per H atom and as shown in figure H atoms didn't get any lone pair of electrons.