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murzikaleks [220]
2 years ago
13

A girl attempts to drink a large glass of water without stopping. when she finishes, she gasps for air as she was unable to brea

th while drinking. question 26 options: inherited learned conditioning imprinting
Physics
1 answer:
katrin [286]2 years ago
4 0

The behaviour that has just been displayed by the girl is an example of a learned behavior.

<h3>What is learned behaviour?</h3>

The term learned behaviour has to do with those behaviour that the individual acquires by practise and are not innate in the organism. The ability to drink a large amount of water without breathing is not inate in man.

Hence, the behaviour that has just been displayed by the girl is an example of a learned behavior.

Learn more about learned behavior:brainly.com/question/347230

#SPJ4

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Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of
Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of  0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

where f is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

f_{n} = \frac{1}{2\pi } \sqrt{\frac{k}{14m} }

simplifying, we have

f_{n} = \frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }

f_{n} = \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }

if we divide this final frequency by the original frequency, we'll have

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  ÷  \frac{1}{2\pi } \sqrt{\frac{k}{m} }

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  x  2\pi \sqrt{\frac{m}{k} }

==> 1/3.742 = <em>0.27</em>

7 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
3 years ago
Read 2 more answers
What is an<br> example of a force?<br> Pressure<br> Power<br> Energy<br> Weight
Kryger [21]

Answer:

weight

Explanation:

weight is the pull of gravity so its a force !!

5 0
3 years ago
Easy one - giving brainly if correct.​
lana66690 [7]

Gas.

HOPE YOU GET 100!

4 0
2 years ago
What does "Position (m)” represent in the graph?
SCORPION-xisa [38]
<span>Position (m)” represent  <u>t</u></span><u>he dependent variable</u> in the graph.
5 0
4 years ago
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