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MA_775_DIABLO [31]
3 years ago
10

A simple pendulum consisting of a small object of mass m attached to a string of length l has a period T.

Physics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

Check Explanation.

Explanation:

For a simple pendulum, the period is given as

T = 2π√(L/g)

It is also given as

T = 2π√(m/k)

where

T = period of oscillation

m = mass of the pendulum

L = length

g = acceleration due to gravity

k = force constant

Equating this two equations,

2π√(L/g) = 2π√(m/k)

(L/g) = (m/k)

(m/L) = (k/g)

So, any pendulum that will have the same period as our pendulum with mass, m, and length, L, must have the ratio of (L/g) to be the same as the pendulum under consideration and the ratio of its mass to force constant (m/k) must also be equal to this ratio.

Hope this Helps!!!

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Answer:

c. Smaller than.

Explanation:

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The right option is c. Smaller than.

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Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. “You see, your Honor, as I was appro
natta225 [31]

Answer and Explanation:

Greetings!

I'm~Isabelle~Williams~and~I~will~be~answering~your~question!

Given:

Wave~length~ of~  red ~ light = 683~  nm

Wave ~length ~of~ yellow~ light = 576~ nm

The~ speed ~of~ the~ Slick~ Willy~ can~ be:

\boxed{~f'=(\frac{v+v_{o} }{v} )f~}

Where:

f'=observed~frequency

f=actual~frequency

v=speed~of~light

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Plug~in~the~values:

683\times 10^-^9=576\times 10^-^9 ~(1+\frac{v_{o} }{3\times 10^8} )

\frac{683}{576}=1+\frac{v_{o} }{3\times 10^8}

\frac{v_{o} }{3\times 10^8}  =\frac{683}{576}=-1

v_{o}=0.186\times 3\times 10^8

v_{o}=0.558\times 10^8 ~m/s

Hope~this~helps!~Have~an~amazing~day~ahead!~

-Isabelle~Williams

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are you asking how the planets are arranged

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