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AlexFokin [52]
2 years ago
10

Object A is placed on top of object B. Object A is the same temperature as object B. How will heat flow between object A and obj

ect B?
A.Heat will flow from object A to object B.
B.No heat will flow between object A and object B.
C.Heat will flow from object B to object A.
Physics
2 answers:
Alex17521 [72]2 years ago
8 0

Answer:

B.No heat will flow between object A and object B.

Explanation:

As we know that heat will flow due to temperature gradient so in all cases the flow of thermal energy is from high temperature to low temperature

So whenever thermal energy is transferred then it has tendency to make the two objects into thermal equilibrium

At the condition of thermal equilibrium the net flow of heat from one object to other object is always zero

So here when object A is placed on the top of object B then in that case it is given that the temperature of two objects are same here.

So these objects are already in thermal equilibrium so there is no net heat flow.

so correct answer will be

B.No heat will flow between object A and object B.

mash [69]2 years ago
6 0
"No heat will flow between object A and object B" is the one among the following choices given in the question that describes how heat will <span>flow between object A and object B. The correct option among all the options that are given in the question is the second option or option "B". I hope it helps you.</span>
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A charge of +2.00 x 10^-9 C is placed at the origin, and another charge of +4.50 x 10^-9 C is placed at x = 1.6 m. The Coulomb c
igor_vitrenko [27]

Answer:

0.64 m from the first charge

Explanation:

Force is given by

F_1=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F_1=\dfrac{k2\times 10^{-9}\times 3.7\times 10^{-9}}{x^2}

F_2=\dfrac{kq_2q_3}{r^2}\\\Rightarrow F_1=\dfrac{k4.5\times 10^{-9}\times 3.7\times 10^{-9}}{(1.6-x)^2}

These forces are equal

\dfrac{k2\times 10^{-9}\times 3.7\times 10^{-9}}{x^2}=\dfrac{k4.5\times 10^{-9}\times 3.7\times 10^{-9}}{(1.6-x)^2}\\\Rightarrow \dfrac{2}{x^2}=\dfrac{4.5}{(1.6-x)^2}\\\Rightarrow \dfrac{2}{4.5}=\dfrac{x^2}{(1.6-x)^2}\\\Rightarrow \dfrac{4.5}{2}=\dfrac{(1.6-x)^2}{x^2}\\\Rightarrow \sqrt{\dfrac{4.5}{2}}=\dfrac{1.6-x}{x}\\\Rightarrow 1.5=\dfrac{1.6-x}{x}\\\Rightarrow 1.5x+x=1.6\\\Rightarrow x=\dfrac{1.6}{2.5}\\\Rightarrow x=0.64\ m

The distance that charge should be placed is 0.64 m from the first charge

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3 years ago
Question 13 (1 point)
Leviafan [203]

Answer:

papa's donuteria

Explanation:

:rawr:

8 0
3 years ago
How many kcalories are provided by a food that contains 25 g carbohydrate, 6 g protein, and 5 g fat?
MrRissso [65]

<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.

Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.

Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.

Simply put it, take note of the following conversions:

  • 1 gram of carbohydrate is 4kcal
  • 1 gram of protein is also 4kcal
  • Though, 1 gram of fat is 9kcal

So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.

1.    25g x 4kcal/g = 100kcal

2.    6g x 4kcal/g = 24kcal

3.    5g x 9kcal/g = 45kcal

4.    100kcal + 24kcal + 45kcal = 169kcal!


Therefore, the food contains 169 kilo-calories!

You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283

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7 0
2 years ago
A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper c
Zolol [24]

Answer:

150.8 J

Explanation:

The heat released by the copper wire is given by:

Q=mC_s \Delta T

where:

m = 10.0 g is the mass of the wire

Cs = 0.377 j/(g.C) is the specific heat capacity of copper

\Delta T=40.0 C - 80.0 C=-40.0 C is the change in temperature of the wire

Substituting into the equation, we find

Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J

And the sign is negative because the heat is released by the wire.

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Studentka2010 [4]

Answer:

Yes

Explanation:

The farther something is from the center of mass of an object such as a planet, the lower the gravitational force between them

F = GMm/d²

4 0
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