Answer:
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Explanation:
Using Bernoulli's Theorem
1/2 V12 +P1/d = 1/2V22 +P2/d
V1 = 17.4
V2 =0
1 /2 V12 = Pressure Difference / d
Where d = Density of air
Pressure Difference =( 1/2 V12) Density of air
Pressure Difference = 369.36
Force = Pressure difference * area = 369.36 *3.5 = 1292.8 N
It will move 1.5 minutes before it comes to a stopping point.
Answer:
The maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°
Explanation:
Given;
coefficient of static friction, μ = 0.4
for the block to remain stationary on the inclined plane, force pushing the block upward must be equal to the force acting downwards.
μR = mgsinθ
μmgcosθ = mgsinθ
μcosθ = sinθ
μ = sinθ/cosθ
μ = tanθ
θ = tan⁻¹(0.4) = 21.8°
Therefore, the maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°