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mafiozo [28]
3 years ago
10

How are sea breezes formed?

Physics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer:

A- when hot air above the hot sand rises then cool air above the ocean replaces it

tekilochka [14]3 years ago
4 0

Answer:

the answer is A

when air above the hot sand rises then cool air above the ocean replaces it

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WILL MAKE BRAINLYEST!!!!!! PLZ HELP
mylen [45]

Answer:

D.

Explanation:

4 0
3 years ago
A truck speeds up from velocity of 6m/s to 14m/s in 4 seconds. what is the trucks acceleration?
Tanzania [10]

To calculate the acceleration of the truck, we use the equation of motion

v = u + at

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given,  u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\  a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } =  2 \ m /s^2.

Thus,  the truck acceleration is 2 \ m /s^2

3 0
3 years ago
Please help !! ASAP
umka2103 [35]

Answer:

22) 5.6 Kg.m/s

23) 0.067 Kg

24) 1.16 m/s

Explanation:

Momentum is found by multiplying mass and velocity

P=mv where P is momentum, m is mass of object and v is the velocity

22

Given

Mass, m=2 Kg

Rate, v=2.8 m/s

Relationship

P=mv

Solution

P=mv=2*2.8=5.6 Kg.m/s

23

Given

Momentum, p=0.1 Kg.m/s

Rate, v=1.5 m/s

Relationship

P=mv and making m the subject then

m=\frac {P}{v}

Solution

m=\frac {0.1 Kgm.s}{1.5 m/s}\approx 0.067 Kg

24

Given

Momentum, p=4.9\times 10^{8} Kg.m/s

Mass, m=4.23\times10^{8} Kg

Relationship

P=mv and making v the subject then

v=\frac {P}{m}

Solution

m=\frac {4.9\times 10^{8}  Kgm.s}{4.23\times10^{8} }\approx 1.16 m/s

5 0
2 years ago
Which statement best describes how scientists and engineers work together in the research and development cycle? A. Scientists t
Pavlova-9 [17]

Answer:

c

Explanation:

7 0
3 years ago
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What is one example of refraction
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Refraction of light is the process we take advantage of when we use eyeglasses.
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3 years ago
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