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3 years ago

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Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45-m-diamete

r semicircles. A greyhound can run around these turns at a constant speed of 15 m/s. What is its acceleration in m/s2
and in units of g?

1 answer:

Margarita [4]3 years ago

5 0

Explanation:

It is given that,

Diameter of the semicircle, d = 45 m

Radius of the semicircle, r = 22.5 m

Speed of greyhound, v = 15 m/s

The greyhound is moving under the action of centripetal acceleration. Its formula is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(15)^2}{22.5}$

$a=10\ m/s^2$

We know that, $g=9.8\ m/s^2$

$a=\dfrac{10\times g}{9.8}$

$a=1.02\ g$

Hence, this is the required solution.

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The tension force on the child's neck when he raises his head from the wall of the slide, $T_{s} = ?$

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