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inn [45]
3 years ago
8

A hair dryer draws a current of 10 A plugged into a 120 V outlet. What is the resistance of the hair dryer?

Physics
2 answers:
Ganezh [65]3 years ago
8 0
<span>This problem can be solved by the formula used to find resistance. The formula is R=V/I which basically means divide the Voltage by the Current to find the Resistance in an object. Ohm's law.</span>
Arada [10]3 years ago
8 0

<u>Answer:</u> The resistance of the hair dryer is 12\Omega

<u>Explanation:</u>

Ohm's law is defined as the law which gives us the relationship between voltage, resistance and current.

Mathematically,

V=I\times R

where,

V = voltage of the hair dryer = 120 V

I = current of the hair dryer = 10 A

R = resistance of the hair dryer = ?

Putting values in above equation, we get:

120=10\times R\\\\R=\frac{120}{10}=12\Omega

Hence, the resistance of the hair dryer is 12\Omega

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Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?
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Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

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Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

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Now,

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

7 0
3 years ago
A body of mass 5 kg has a velocity<br><br><br>20 MS <br><br>-1 its Momentum is​
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a 25-N net force is applied to a rolling cart and pruduces an acceleration of 5 m/s 2 what’s the cart mass
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The mass of the cart is 5 kg

Explanation:

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