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inn [45]
3 years ago
8

A hair dryer draws a current of 10 A plugged into a 120 V outlet. What is the resistance of the hair dryer?

Physics
2 answers:
Ganezh [65]3 years ago
8 0
<span>This problem can be solved by the formula used to find resistance. The formula is R=V/I which basically means divide the Voltage by the Current to find the Resistance in an object. Ohm's law.</span>
Arada [10]3 years ago
8 0

<u>Answer:</u> The resistance of the hair dryer is 12\Omega

<u>Explanation:</u>

Ohm's law is defined as the law which gives us the relationship between voltage, resistance and current.

Mathematically,

V=I\times R

where,

V = voltage of the hair dryer = 120 V

I = current of the hair dryer = 10 A

R = resistance of the hair dryer = ?

Putting values in above equation, we get:

120=10\times R\\\\R=\frac{120}{10}=12\Omega

Hence, the resistance of the hair dryer is 12\Omega

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3 years ago
The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of
alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

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C = \frac{\epsilon_0 A}{d}

Where,

\epsilon_0 = Permeability constant

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Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to \rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

Q = CV

Q = \frac{\epsilon A}{d}(Ed)

Q = \epsilon_0 AE

Q = \epsilon_0 \pi(\frac{d}{2})^2E

Q = \frac{\epsilon \pi d^2E}{4}

Re-arranging the equation to find the diameter of the disks, the equation will be:

d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}

Replacing,

d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}

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Answer:

The value is }  N  =  66 \  blocks

Explanation:

From the question we are told that

The weight of the block is W_b  = 100 \  N

The dimension of the block is d =  0.400 m  \ X  \ 0.250 \  m  \  X  \ 0.130 \ m

Generally two atmosphere is equivalent to

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So

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=> A =  0.0325 \  m^2

Generally the force due to this blocks is mathematically represented as

F =  N  *  W_b

Here N is the number of blocks

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}  202600 =  \frac{N  *  100 }{ 0.0325}

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