Based on the information, both technician A and technician B are correct.
<h3>How to depict the information?</h3>
From the information given, Technician A says that mechanical shifting controls can wear out over time.
Technician B says that vacuum control rubber diaphragms can deteriorate over time.
In this case, both technicians are correct as the information depicted is true.
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The rate of gain for the high reservoir would be 780 kj/s.
A. η = 35%

W = 
W = 420 kj/s
Q2 = Q1-W
= 1200-420
= 780 kJ/S
<h3>What is the workdone by this engine?</h3>
B. W = 420 kj/s
= 420x1000 w
= 4.2x10⁵W
The work done is 4.2x10⁵W
c. 780/308 - 1200/1000
= 2.532 - 1.2
= 1.332kj
The total enthropy gain is 1.332kj
D. Q1 = 1200
T1 = 1000

<h3>Cournot efficiency = W/Q1</h3>
= 1200 - 369.6/1200
= 69.2 percent
change in s is zero for the reversible heat engine.
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In order to fly, you must have a device/mechanism that will release hot air, causing it to fly. A jet pack will do the job.
You always need some company