Answer:
- import java.util.Scanner;
- public class TryToParseDouble {
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
- double num;
-
- try{
- System.out.print("Input a number: ");
- num = Double.parseDouble(input.nextLine());
-
- }catch(NumberFormatException e){
- num = 0;
- System.out.println("Invalid input! It should be a number in double type");
- }
- System.out.println(num);
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 5).
Next, create a try block and prompt user to input a number and use Double.parseDouble() method to convert the input to double type in the block (Line 8-10).
Next, create a catch block to catch a NumberFormatException. In the Catch block, set the num to zero and then print out a message to inform user about the invalid input (Line 12-14).
Lastly, display the number (Line 16).
Answer: You're question is very vague... be more specific in the problem, what is it asking you to do?
Explanation: This shouldn't be under "Engineering" you should put it under "Mathematics" for a better result. Sorry for the mix up! Hope this helps! ^^
Differential Stress are known to be actions that squeeze or push on a rock are stronger in some directions than others.
<h3>What is Differential Stress?</h3>
Differential stress is known to be a kind of difference that do exist between the greatest and the least compressive stress that is experienced by a specific object.
The term is used in geological and civil engineering and it is known to be the greatest compressive stress as Differential Stress are known to be actions that squeeze or push on a rock are stronger in some directions than others.
Learn more about Differential Stress from
brainly.com/question/4902351
Answer:
Explanation:
Given that :
The strength and stability of tires may be enhanced by heating both sides of the rubber ( 0.14 W/m·K, 6.35 × 10^-8m^2/s)
i.e
k = 0.14 W/mK
∝ = 6.35 × 10⁻⁸ m²/s
L = 0.01 m
We cannot use the model of Lumped Capacitance; SO Let assume that Fourier Number 
⇒ 
From Table 5.1 ; at 
= 14.2857
![\dfrac{170-200}{35-200} = 1.265 exp [ - (1.458)^2* \dfrac{ \alpha t_f}{L^2}]](https://tex.z-dn.net/?f=%5Cdfrac%7B170-200%7D%7B35-200%7D%20%3D%201.265%20exp%20%5B%20-%20%281.458%29%5E2%2A%20%5Cdfrac%7B%20%5Calpha%20t_f%7D%7BL%5E2%7D%5D)
Answer:
False
Explanation:
<u>Alternat</u>or produces <u>alternat</u>ing current ....diodes convert this to direct current
