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Ymorist [56]
2 years ago
8

Writing an excellent problem statement will not help guide you through the rest of the process and steer you towards the BEST so

lution. True False
Engineering
1 answer:
Ilya [14]2 years ago
4 0

Answer:

Writing an excellent problem statement will not help guide you through the rest of the process and steer you towards the BEST solution.

False

Explanation:

An excellent problem statement sets the overall tone for the rest of the engineering process, whether it be at the analysis, design, or implementation stages.  This is why a problem statement must be focused, clear, and specific.  An excellent problem statement contains the problem definition, method for solving the problem (the claim proposed), purpose, statement of objectives, and scope.  For an excellent problem statement to be effective, it must also show the gap that is to be closed to achieve the intended objective.

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I don't have robux

Explanation:

but i love adopt me

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What happens to the duty cycle for a GMAW Gun when 75Ar/25COzgas
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The underground cafe has an operating cash flow of $187,000 and a cash flow to creditors of $71,400 for the past year. During th
Serggg [28]

Answer:

cash flow to stockholders = $39,700

Explanation:

Operating cash flow = $187,000

cash flow to creditors = $71,400

Net working capital = $28,000

Net capital spending =  $47,900

Cash flow to stockholders = ?

CFF = operating cash flow - net working capital - net capital spending

CFF = $187,000 - $28,000 - $47,900 = $111,100

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3 0
3 years ago
The total solids production rate in an activated sludge aeration tank is 7240 kg/d on a dry mass basis. It is necessary to maint
snow_lady [41]

Answer:

volume of biological sludge = 28.566 m³ per day

Explanation:

given data

mass of solid = 7240 kg/day

initial moisture content = 78%

solution

here percentage of solid will be

% of solid = 100 - initial moisture content

% of solid = 100 - 78 = 22 %

so that

mass of sludge produced = \frac{100}{100 - P} M kg  per day

put her value

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mass of sludge produced = 32909.09 kg

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\frac{100}{S sludge} = \frac{solid percentage}{S solid} = \frac{water percentage}{S water}

\frac{100}{S sludge} = \frac{22}{2.5} = \frac{78}{1}

S sludge = 1.152

so that

density of sludge = S sludge × density of water

density of sludge = 1.152 × 1000

density of sludge = 1152 kg/m³

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3 years ago
WIL MARK U AS BRAINLIEST HELP PLZ
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