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Delicious77 [7]
1 year ago
15

What would the atomic mass of an atom if its mass is approximately 12 time that of carbon 12​

Chemistry
1 answer:
Stolb23 [73]1 year ago
6 0

Answer:

144 u

Explanation:

The average atomic mass of carbon is approximately 12 u.

Multiply 12 x 12:

12 x 12 = 144

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They are both sources of power for objects that people use.
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3 years ago
The crater is the bowl-shaped area around a volcano’s central vent. t/f
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If I'm correct, the crater is actually a circular-shaped area around the volcano's central vent. My answer is false
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2 years ago
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
Suppose an adult is encased in a thermally insulating barrier so that all the heat evolved by metabolism of foodstuffs is retain
mihalych1998 [28]
Given:
Q = 9.4 kJ/(kg-h), the heat production rate
c = 4.18 J/(g-K), the heat capacity
t = 2.5 h, amount of time

Note that
c = 4.18 J/(g-K) = 4180 J/(kg-K) = 4.18 kJ/kg-K)

Consider 1 kg of mass.
Then
Qt = cΔT
where ΔT is the increase in temperature (°K)
(1 kg)*(9.4 kJ/(kg-h))*(2.5 h) = (1 kg)*(4.18 kJ/(kg-K))*(ΔT K)
23.5 = 4.18 ΔT
ΔT = 23.5/4.18 = 5.622 K = 5.622 °C

Answer: 5.62 K (or 5.62 °C)

7 0
3 years ago
Why a finely powdered sample should be used in a melting point measurement?
lapo4ka [179]

because it a essential for good heat transfer

6 0
2 years ago
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