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1 year ago

Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?

1 answer:

6 0

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed methyl vinyl ketone.

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed methyl vinyl ketone.

It can be written as

$CH_{2} O + CH_{3} COCH_{3}$ → $HOCH_{2} -CH_{2} -CO-CH_{3}$

When it will be heated then it gives methyl vinyl ketones.

$HOCH_{2} -CH_{2} -CO-CH_{3}$ → $CH_{2} =CH-CO-CH_{3}$

So, the pair of reactants will be formaldehyde and acetone

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3 years ago

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3 years ago

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antoniya [11.8K]

Hello!

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3 years ago

Do you know how much water could you get if you started with 250.0 grams of hydrogen?

Soloha48 [4]

The amount of water that could we get if you started with 250.0 grams of hydrogen is 2,250 grams.

<h3>What is moles - mass realation?</h3>

Moles (n) and mass of any substance are related to each other according to the given equation as:

n = W/M, where

W = given mass

M = molar mass

Given balanced chemical reaction is:

2H₂ + O₂ → 2H₂O

Moles of 250g of H₂ = 250g / 2g/mol = 125mol

From the stoichiometry of the reaction it is clear that,

2 moles of H₂ = produces 2 moles of H₂O

125 moles of H₂ = produces 125 moles of H₂O

Now mass of water will be calculated as:

Mass = (125mol)(18g/mol) = 2,250g

Hence required mass of water is 2,250 grams.

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