From Gauss law we have
E = 2kx/r where x=linear charge density, r=distance from the wire=1.7 m
k =9 x 10^9 SI units.....we have been given E = 3.8 x 10^4 N/C ..... so plugging numbers we get
x = 3.59 x 10^ -6 C/ M (coulomb per meter) =linear charge density
Answer:
The magnitude of force is 1.86 N and the direction of force is towards the other wire.
Explanation:
Given:
Current flowing through each power line, I = 130 A
Distance between the two power lines, d = 40 cm = 0.4 m
Length of power lines, L = 220 m
The force exerted by the power lines on each other is given by the relation:

Substitute the suitable values in the above equation.

F = 1.86 N
Since the direction of current flowing through the power lines are opposite to each other, so the force is attractive in nature. Hence, the direction of force experienced by the power lines on each other is towards the each other.
Answer:
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Answer:
it appears to be farther away than it actually is, and therefore smaller then the object itself.