1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inysia [295]
2 years ago
6

Solving Problems: Using Ohm's law

Physics
1 answer:
JulijaS [17]2 years ago
8 0
A) Since V = I/R, we know that VR = I so 16 x 24 = 384.

B) I/V = R so 2/6 which = 0.333

and for C i physically cannot open the pic but good luck and use Voltage = Current / Resistence
You might be interested in
What two quantities must stay the same in order for an object to have a constant velocity? A) The speed and kinetic energy must
GarryVolchara [31]

the answer is c) the speed and direction of travel must be constant


7 0
4 years ago
A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so tha
Dvinal [7]

Answer:

0.087 m

Explanation:

Length of the rod, L = 1.5 m

Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.

time period, T = 3  s

the formula for the time period of the pendulum is given by

T = 2\pi \sqrt{\frac{I}{mgd}}    .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

Moment of inertia of the rod about the centre of mass, Ic = mL²/12

By using the parallel axis theorem, the moment of inertia of the rod about the pivot is

I = Ic + md²

I = \frac{mL^{2}}{12}+ md^{2}

Substituting the values in equation (1)

3 = 2 \pi \sqrt{\frac{\frac{mL^{2}}{12}+ md^{2}}{mgd}}

9=4\pi^{2}\times \left ( \frac{\frac{L^{2}}{12}+d^{2}}{gd} \right )

12d² -26.84 d + 2.25 =  0

d=\frac{26.84\pm \sqrt{26.84^{2}-4\times 12\times 2.25}}{24}

d=\frac{26.84\pm 24.75}{24}

d = 2.15 m , 0.087 m

d cannot be more than L/2, so the value of d is 0.087 m.

Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.

3 0
3 years ago
If oxygen and steel wool are combined is it a physical change or chemical change?
Anon25 [30]

Answer:

I think it would be a chemical change.

Explanation:

Because a physical would be like crushing it or something along that line.

4 0
3 years ago
Read 2 more answers
Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S <br>​
Tems11 [23]

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}

6 0
3 years ago
In the Rolling Plains ecoregion of Texas, some parts of rivers are in deep canyons and others have bottoms that are close to the
Serga [27]

Answer:

most likely C

Explanation:

4 0
4 years ago
Read 2 more answers
Other questions:
  • Explain the difference between evaporation and boiling
    6·2 answers
  • If a tree fall in a forest does it make a sound?
    6·1 answer
  • Which two statements are true of electromagnetic waves?
    11·1 answer
  • A car (mass = 1200 kg) is traveling at 31.1 m/s when it collides head-on with a sport utility vehicle (mass = 2830 kg) traveling
    8·1 answer
  • Lillian (mass 40.0 kg) standing at rest on slippery ice catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Wha
    10·1 answer
  • True or false
    9·1 answer
  • Which of the following would NOT be considered vigorous aerobic exercise?
    5·2 answers
  • PLS HELP I NEED ANSWER HOMEWORK DUE SOON
    6·1 answer
  • The photo shows a skateboarder pushing her foot against the ground as she rides down a hill.
    14·1 answer
  • Dust, accumulated at the time of the formation of the solar system is sometimes preserved in asteroids, meteoroids, and meteorit
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!