What is the Force acting on a ball if the mass of the ball is 2 kg and the acceleration of the ball is 5 m/s2?

The acronym laser stands for light amplification by ____ emission of radiation

AleksAgata [21]

<span>light amplification by stimulated emission of radiation </span>

6 0

3 years ago

Choose all of the true statements regarding the relationship between voltage, resistance, and current. Current is measured in am

wel

-- <u><em>Current is measured in amps.</em></u> (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)

-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>

-- <u><em>Current is the flow of electrons through a circuit.</em></u>

-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.) <u><em>It should be V = I · R</em></u> .

(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.) <u><em>If the resistance is what you're looking for, then the equation to use is </em></u><u><em>R = V / I</em></u><u><em> . </em></u>

<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>

6 0

3 years ago

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Name two things that can cause a short circuit in your home?

Dima020 [189]

Plugs exposed to liquid such as water; too many things plugged in at once

3 0

3 years ago

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Suppose you balance a 2-kg ball on the tip of your finger, which has an area of 1 cm2. Show that the pressure on your finger is

Nezavi [6.7K]

For the answer to the question above, we have to use this formula
Pressure = P = force / area
Then, just substitute the values of the formula
force = mg = 2(10) = 20 N

area = A = 1 cm² = [1 x 10 ̄ ²]² m²

=> P = 20 N / [1 x 10 ̄ ²]² = 200 x 10³ Pa

= 200 kPa
I hope my answer helped you. Have a nice day!

5 0

3 years ago

In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it.

Georgia [21]

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

<h3>Final speed of both balls after collision</h3>

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

<h3>Maximum displacement of the balls after the collision</h3>

P.E = K.E

$mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m$

<h3>Maximum angular displacement</h3>

The maximum angular displacement of the balls after the collision is calculated as follows;

$cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0$

<h3>Frequency of the motion</h3>

$f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz$

Learn more about maximum angular displacement here: brainly.com/question/13665036

4 0

2 years ago