What is the Force acting on a ball if the mass of the ball is 2 kg and the acceleration of the ball is 5 m/s2?

If you neglect air resistance, the horizontal component of a projectile A. Is always changing B. Remains constant throughout the

Shtirlitz [24]

Answer:

B. Remains constant throughout the flight

Explanation:

If we completely neglect air resistance then the projectile will not have any horizontal resistances to deal with, therefore the horizontal component will remain constant throughout the flight. This would continue to be the case until it meets some form of resistance. Which assuming that everything else is normal would be the case since the force of gravity will push the projectile down (vertical component) until it hits the ground which in that instance would act as an opposing force to the horizontal component as well.

8 0

3 years ago

Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

$\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)$

$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

now we have

$\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi$

Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

so we have

$\lambda = 0.827$

now we have

$\frac{340}{f} = 0.827$

$f = 411.3 Hz$

4 0

3 years ago

Use distributive property to express 48+72

Stolb23 [73]

10 ( 6+6 ) = 120

random = abcdefghigklmnopqrstuvwxyz

7 0

3 years ago

It is difficult to walk with shoes having heals

Ad libitum [116K]

This question confuses me? are you asking is it difficult to walk WITH high heels?

but to answer your question, it all depends on the person. some people are naturally good at walking in heels and others could have trouble wearing them for too long, or walking normally.

4 0

3 years ago

A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (

marissa [1.9K]

Answer:

a = 12.8 m/s^2

Explanation:

To find the centripetal acceleration you use the following formula:

$a_c=\frac{v^2}{r}$ (1)