Answer:
Which language is this???
Okay so,
1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced
2) mRNA leaves the cell and joins with a ribosome
3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished
4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)
Hope this helps :)
Explanation:
The given data for case (1) is as follows.
h = 20 cm = 0.2 m
Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.
Q =
where, A = area
L = length
k = thermal conductivity = 0.8 W/m
= change in temperature.
Therefore, putting the given values into the above formula as follows.
Q =
=
= 168 W
For case (2), h = 180 cm = 1.8 m
Therefore, heat lost will be calculated as follows.
Q =
=
= 18.67 W
Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.
Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97