Consider a uniform electric field of 50 N/C directed toward the east. If the voltage measured relative to ground at a given poin
t in the field is 80 V, what is the voltage at a point 1.0 m directly east of the point
1 answer:
Answer:
30 V
Explanation:
Given that:
The uniform electric field = 50 N/C
Voltage = 80 V
distance = 1.0 m
The potential difference of the electric field = Δ V
E_d = V₁ - V₂
50 × 1 = 80V - V₂
50 - 80 V = - V₂
-30 V = - V₂
V₂ = 30 V
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