Explanation :
It is given that,
Diameter of the coil, d = 20 cm = 0.2 m
Radius of the coil, r = 0.1 m
Number of turns, N = 3000
Induced EMF, ![\epsilon=1.5\ V](https://tex.z-dn.net/?f=%5Cepsilon%3D1.5%5C%20V)
Magnitude of Earth's field, ![B=10^{-4}\ T](https://tex.z-dn.net/?f=B%3D10%5E%7B-4%7D%5C%20T)
We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :
![\epsilon=NBA\omega](https://tex.z-dn.net/?f=%5Cepsilon%3DNBA%5Comega)
![\omega=\dfrac{\epsilon}{NBA}](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B%5Cepsilon%7D%7BNBA%7D)
![\omega=\dfrac{1.5}{3000\times 10^{-4}\times \pi (0.1)^2}](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B1.5%7D%7B3000%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20%5Cpi%20%280.1%29%5E2%7D)
![\omega=159.15\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D159.15%5C%20rad%2Fs)
So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.
Answer:
the energy difference between adjacent levels decreases as the quantum number increases
Explanation:
The energy levels of the hydrogen atom are given by the following formula:
![E=-E_0 \frac{1}{n^2}](https://tex.z-dn.net/?f=E%3D-E_0%20%5Cfrac%7B1%7D%7Bn%5E2%7D)
where
is a constant
n is the level number
We can write therefore the energy difference between adjacent levels as
![\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%20%28%5Cfrac%7B1%7D%7Bn%5E2%7D-%5Cfrac%7B1%7D%7B%28n%2B1%29%5E2%7D%29)
We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is
![\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B1%5E2%7D-%5Cfrac%7B1%7D%7B2%5E2%7D%29%3D-13.6%20eV%281-%5Cfrac%7B1%7D%7B4%7D%29%3D-13.6%20eV%28%5Cfrac%7B3%7D%7B4%7D%29%3D-10.2%20eV)
While the difference between the levels n=2 and n=3 is
![\Delta E=-13.6 eV(\frac{1}{2^2}-\frac{1}{3^2})=-13.6 eV(\frac{1}{4}-\frac{1}{9})=-13.6 eV(\frac{5}{36})=-1.9 eV](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B3%5E2%7D%29%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B4%7D-%5Cfrac%7B1%7D%7B9%7D%29%3D-13.6%20eV%28%5Cfrac%7B5%7D%7B36%7D%29%3D-1.9%20eV)
And so on.
So, the energy difference between adjacent levels decreases as the quantum number increases.
Answer:
Startinfg speed is 13.82 m/s
Explanation:
Use equation for realtion between start and final speed :
Vf=Vs+a*t
Vf-final speed
Vs-start speed
Vf=24.44m/s
a=1.77m/s²(acceleration)
t=6.00s(Time)
Vf=Vs+a*t
Vs=a*t-Vf
Vs=1.77m/s²*6s-24.44m/s
Vs=-13.82m/s
That would be a maximum of 4 atoms
Answer:
Newton's third law is: For every action, there is an equal and opposite reaction.
Explanation:
The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.