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3 years ago

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A man claims that he can hold onto a 13.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man

in a collision in which he is in one of two identical cars each traveling toward the other at 59.0 mi/h relative to the ground. The car in which he rides is brought to rest in 0.11 s.

1 answer:

Softa [21]3 years ago

4 0

Answer:

F = 3116.49 N

Explanation:

given,

mass of the child = 15 kg

speed = 59 mi/hr

time taken to come to rest = 0.11 s

force on the boy = ?

1 mi/hr = 0.447 m/s

59 mi/hr = 59 × 0.447 = 26.37 m/s

$a = \dfrac{dv}{dt}$

$a = \dfrac{26.37}{0.11}$

a=239.73 m/s²

the calculation of force

Force = mass × acceleration

F = m × a

F = 13 × 239.73

F = 3116.49 N

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