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4 years ago

Examine the equation.

Chemistry

2 answers:

jenyasd209 [6]4 years ago

7 0

Answer:

Coefficient

Explanation:

We can explain this discarting options too. Now, let's write again the chemical equation;

C3H8(g)+5O2(g)→3CO2(g)+4H2O(l)

In a chemical equation, we have two sides. The left side we have the reactants of the reaction, these can be elements or compounds that reacts between each other, to produce another compound or substance. This compounds or elements are on the right side of the reaction. This side we have the products of the reaction of reactants.

Now, as in every situation of life, we need a balance of reactants and products, so, the only way to balance a chemical equation is by putting numbers behind every compound of the reactant and/or products to equal the number of atoms on each side. So if in the reactants we have 3 atoms of C, in the products we need to have the same 3 atoms.

Based on the above explanation, we can say that the number 4 is behind the H2O. This compound is on the side of products, but the number only, do not represent a product, so this option can be discarted.

A reactant cannot be either, cause it's not on the side of reactant.

Chemical formula, could be, if the number were as subscript, but it's not the case, and the chemical formula is composed of symbols.

Finally, as the number that we put behind the compounds work to balance the equation, the only function that these numbers have here, is to be coefficients of the reactions, and furthermore, it will work as mole.

So the correct option is the third one, Coefficient.

azamat4 years ago

3 0

4 is a coefficient of the formula

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A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

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3 years ago

How many grams of barium chloride are produced when 1.25 x 1023 molecules of HCl reacts with barium?

sp2606 [1]

Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.

<h2>Balanced reaction</h2>

The balanced reaction is

2 HCl + Ba → BaCl₂ + H₂

<h2>Moles of HCl that react</h2>

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?

amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms

<u><em>amount of moles of HCl= 0.2075 moles</em></u>

Then, 0.2075 moles of HCl react.

<h2>Reaction stoichiometry</h2>

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole

<h2>Mass of barium chloride produced</h2>

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?

$amount of moles of BaCl_{2} =\frac{0.2075 moles of HCl x 1 mole of BaCl_{2} }{ 2moles of HCl}$

<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>

Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:

$0.10375 molesx\frac{208.24 grams}{1 mole} =21.6 grams$

Finally, the mass of barium chloride produced is 21.6 grams.

Learn more about:

Avogadro's Number

Reaction stoichiometry

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3 years ago