Answer:
v = 5.949 m / s
, a = 59.18 m / s²
Explanation:
Linear and angular quantities are related
v = w r
we search the magnitudes to the SI system
w = 95 rev / min (2π rad / 1rev) (1 min / 60 s) = 9.948 rad / s
d = 598 mm = 0.598 m
a) let's calculate the linear velocity
v = 9.948 0.598
v = 5.949 m / s
b) Cenripetal acceleration
a = v² / r
a = 5.94 2 / 0.598
a = 59.18 m / s²
Answer:
Explanation:
given,
A woman can see object between 45 cm and 155 cm
glasses is 2 cm from the eye
to able to read a book distance = 25 cm
For the object distant apart
hence, D = - 0.653 m
For the object at the near point
hence, D = 2.02 m
Answer:
Explanation:
In order to find the force between the two electrons, we need to use Coulomb's law. In its scalar form, the law is given by:
Where:
The electric charge of an electron is a known constant given by:
So:
Therefore, replacing the data provided in the Coulomb's law equation:
The main morphological types of galaxies are elliptical, spiral, and irregular.
Based on their morphology , galaxies have been classified into 3 types namely elliptical, spiral, and irregular.
These galaxies have various sizes and shapes ranging from dwarf galaxies to giant galaxies.
Elliptical Galaxy:
- The shape of it is generally circular
- These are the largest among all the types of galaxies because according to astronomers, it is formed by the merger of other small galaxies.
- Their rotational pattern is symmetric.
Spiral Galaxy:
- A spiral galaxy consists of a bright nucleus surrounded by a thin outer disk forming a spiral shape.
- This type of galaxy is the most common in our universe.
- It is divided into three classes: Spiral a, Spiral b, and Spiral c.
- Their rotational pattern has circular symmetry.
Irregular Galaxy:
- These types of galaxies have no central nucleus and irregular arms which are bluish.
- They don’t have any rotational symmetry.
To know more about "galaxies", refer to the following link:
brainly.com/question/24836631?referrer=searchResults
#SPJ4
Answer:
378 KWh
Explanation:
We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:
10³ W = 1 KW
Therefore,
1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W
1.2×10³ W = 1.2 KW
Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:
60 mins = 1 h
Therefore,
6.3×10² mins = 6.3×10² mins × 1 h / 60 mins
6.3×10² mins = 10.5 h
Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:
Power (P) = 1.2 KW
Time (t) for 1 month (30 days) = 10.5 h × 30
= 315 h
Energy (E) =?
E = Pt
E = 1.2 × 315
E = 378 KWh
Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.
