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1 year ago

6

Identify the amplitude of the wave using the picture below.

1 answer:

konstantin123 [22]1 year ago

4 0

Answer:

Line 2 is the amplitude

Explanation:

The amplitude is the distance from equilibrium to the top of the maximum or minimum of the wave.

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. A rope is being used to pull a mass of 10 kg vertically upward. Determine the tension on the rope, if starting from rest, the

telo118 [61]

$\text{Given that,}\\\\\text{Mass, m =10 kg}\\\\\text{Time, t = 8 sec}\\\\\text{Velocity, v = 4~m/s}\\\\\text{When a body is moving upwards,}\\\\\text{Tension,}~ T=mg +ma\\\\~~~~~~~~~~~~~~~=mg+m\left(\dfrac{v-u}t \right)\\\\~~~~~~~~~~~~~~~=10(10)+10\left(\dfrac{4-0}8\right)\\\\~~~~~~~~~~~~~~~=100+10\left(\dfrac 12\right)\\\\~~~~~~~~~~~~~~~=100+5\\\\~~~~~~~~~~~~~~~=105~N$

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2 years ago

A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed

sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

$Fd = \frac{1}{2} m (v_i^2- v_f^2)$

where,

$v_f = 0$

$F = u_kmg$

$(\mu_kg) d = \frac{1}{2} m v_i^2$

$d = \frac{\frac{1}{2}v_i^2}{\mu_kg}$

$d = \frac{v_i^2}{2 \mu_kg}$

b. The initial speed of the carton if the factor of 3 risen, so the expression is

$v_i^1 = 3v_i$

$d^i = \frac{(3v_i^2)}{2\mu_kg}$

$= \frac{9v_i^2}{2\mu_kg}$

$d^i = 9(d)$

8 0

3 years ago

Two positive charged particles will ?

Vika [28.1K]

Answer:

make a negative

Explanation:

yep

6 0

3 years ago

Read 2 more answers

What is the approximate initial height of the counterweight?

BabaBlast [244]

Answer: I don't know this one but I'm just came here for points

Explanation:

5 0

2 years ago

Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

xxMikexx [17]

Answer:

Frequency of the light will be equal to $6.97\times 10^{1}Hz$

Explanation:

We have given wavelength of the light $\lambda =430nm=430\times 10^{-9}m$

Velocity of light is equal to $v=3\times 10^8m/sec$

We have to find the frequency of light

We know that velocity is equal to $v=\lambda f$ , here $\lambda$ is wavelength and f is frequency of light

So frequency of light will be equal to $f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz$

So frequency of the light will be equal to $6.97\times 10^{1}Hz$

5 0

2 years ago