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3 years ago

Which element has a complete valence electron shell?

Chemistry

2 answers:

borishaifa [10]3 years ago

7 0

Argon, it's a noble gas in the last group on the periodic table.

aliina [53]3 years ago

6 0

Argon is your answer

Hope this helps!

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How many covalent bonds are there in one molecule of carbon dioxide, CO2?

Nutka1998 [239]

It would be two because there’s 1 Carbon and 2 oxygen

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3 years ago

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In an experiment, potassium chlorate decomposed according to the following chemical equation.

Arada [10]

Answer:

(240 × 3 × 31.998)/(122.5 × 2) g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 122.5 31.998

2KClO₃ ⟶ 2KCl + 3O₂

Mass/g: 240

Mass of O₂ = 240 g KClO₃ × (1 mol KClO₃/122.5 g KClO₃) × (3 mol O₂/2 mol KClO₃) × (31.998 g O₂/1 mol O₂) = 94.0 g O₂

Mass of O₂= (240 × 3 × 31.998)/(2 × 122.5) = 94.0 g O₂

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3 years ago

Explain what happens to the energy in a wave when a sound is louder.

liraira [26]

Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less. This explains why even loud sounds fade away as you move farther from the source.

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3 years ago

Which is the best method for organizing information collected in an investigation? Plz help

Elden [556K]

Construct a table i think

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3 years ago

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Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o

sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is 4.50 × 10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50 × 10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

$[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4} } = 0.0106 M$

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

$\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%$

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3 years ago