The volume in the pump when the pump piston is all the way down represents the end systolic volume.
<h3>
What is systolic volume?</h3>
End systolic volume is the volume of blood in a ventricle at the end of contraction, or systole, and the beginning of filling, or diastole.
End systolic volume is the lowest volume of blood in the ventricle at any point in the cardiac cycle.
Thus, the volume in the pump when the pump piston is all the way down represents the end systolic volume.
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Answer:
option D
Explanation:
also to add.... there exists a solubility equilibrium between solid solute and the solution.
A) gneiss
Explanation:
The likely rock that would be found here is gneiss.
A rock type that forms under a great deal of temperature and pressure is a metamorphic rock.
Such rocks would have their minerals crystallized when subjected to these extreme conditions.
- Metamorphic rocks are changed rocks that are formed when minerals in rocks are subjected to extreme pressure and temperature before they start melting.
- These rock type can form from either sedimentary or igneous rocks. In fact a metamorphic rock can also change into another one.
- Examples of metamorphic rocks are gneiss, schist, hornfels, marble etc.
Halite, limestone and sandstone are examples of sedimentary rocks that forms by the accumulation of sediments or precipitation of ions form solutions.
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Answer:
a) n = 9.9 b) E₁₀ = 19.25 eV
Explanation:
Solving the Scrodinger equation for the electronegative box we get
Eₙ = (h² / 8m L²2) n²
where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number
In this case En = 19 eV let us reduce to the SI system
En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J
n = √ (In 8 m L² / h²)
let's calculate
n = √ (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²
n = √ (98) n = 9.9
since n must be an integer, we approximate them to 10
b) We substitute for the calculation of energy
In = (h² / 8mL2² n²
In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 10²
E₁₀ = 3.08 10⁻¹⁸ J
we reduce eV
E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)
E₁₀ = 1.925 101 eV
E₁₀ = 19.25 eV
the result with significant figures is
E₁₀ = 19.25 eV
