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4 years ago

How much net force needed to accelerate a 3 kg skateboard at 5m/s?

Physics

1 answer:

emmasim [6.3K]4 years ago

6 0

Answer:

The answer is 15N!

Explanation:

F=MA (Force = Mass * Acceleration).

F = 3 * 5 which is 15 N (newtons).

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Calculate the intensity of current flowing through a computer that consumes 180W and operates at 120 V.

padilas [110]

Answer:

C) 1.5 A

Explanation:

P = IV

180 W = I (120 V)

I = 1.5 A

5 0

3 years ago

Which two elements have similar characteristics?

joja [24]

Lithium and calcium because they are in the same group.

7 0

3 years ago

Read 2 more answers

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magni

d1i1m1o1n [39]

Answer:

a) 1.62*10^{-18}N

b) 2.84*10^{-19}N

c) 1.16*10^{-18}N

Explanation:

The net force is given by the expression:

$\vec{F}=q(\vec{E}+\vec{v}\ X\ \vec{B})$

By the right hand rule, we know that the direction of the magnetic force is

j X -i = k

$\vec{v}X\vec{B}=vB\hat{k}$

Hence, the direction of the magnetic force is the +z direction.

(a) E=4.19V/m k

$F=(1.6*10^{-19}C)[4.19\frac{V}{m}+(2540\frac{m}{s})(2.35*10^{-3}T)]=1.62*10^{-18}N$

where we have used q=9.1*10^{-31}kg.

(b) E=-4.19V/m k

$F=(1.6*10^{-19}C)[-4.19\frac{V}{m}+(2540\frac{m}{s})(2.35*10^{-3}T)]=2.84*10^{-19}N$

In this case the net force will have two components:

$F=(1.6*10^{-19}C)[4.19\frac{V}{m}\hat{i}+(2540\frac{m}{s})(2.35*10^{-3}T)\hat{k}]\\\\F=[6.704*10^{-19}\hat{i}+9.55*10^{-19}\hat{k}]N$

and its magnitude will be:

$F=\sqrt{(6.704*10^{-19})^2+(9.55*10^{-19})^2}=1.16*10^{-18}N$

hope this helps!!

5 0

3 years ago

Give three examples from your life of magnetic force.

Margaret [11]

Headphones, refrigerator magnets, and compasses

Hope that was helpful.

4 0

3 years ago

Read 2 more answers

The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate ride

Mariulka [41]

Answer:

A. 1222,10 N

Explanation:

First, we determine the value of the acceleration that the hydraulic launching system must guarantee. Let’s remember that the definition of acceleration is the rate of change of velocity with respect to time. Therefore:

a_hyd = ∆v/∆t = (54 m/s-0)/(3,8 s-0) = 14,21 m/s^2

According to Newton’s second law:

∑F_net = m*a = 86 kg*14,21 m/s^2 = 1222,10 N

So, the net force required to accelerate an 86-kg man is 1222,10 N

Have a nice day! :D

3 0

4 years ago