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victus00 [196]
4 years ago
7

How much net force needed to accelerate a 3 kg skateboard at 5m/s?

Physics
1 answer:
emmasim [6.3K]4 years ago
6 0

Answer:

The answer is 15N!

Explanation:

F=MA (Force = Mass * Acceleration).

F = 3 * 5 which is 15 N (newtons).

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50kg driving at 30kph because it’s the heaviest yet fastest!
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Temperature is generally proportional to a substance's _______.
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rotational kinetic energy of it's particles

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4 years ago
A train travels due south at 25 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of e
olasank [31]

Answer:

Explanation:

Given

Train travels towards south with a velocity if v_t=25\ m/s

Rain makes an angle of \theta =66^{o}  with vertical

If an observer sees the drop fall perfectly vertical i.e. horizontal component of rain velocity is equal to train velocity

suppose v_r is the velocity of rain with respect to ground then

v_r\sin\theta =v_t

v_r\times \sin (66)=25

v_r=27.36\ m/s

Therefore velocity of rain drops is 27.36 m/s              

8 0
3 years ago
A heat engine does 300 J of work during one cycle. In this cycle 900 J of energy is wasted.
andreyandreev [35.5K]
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7 0
3 years ago
Read 2 more answers
A bullet is shot horizontally from shoulder height (1.5 m) with an initial speed 200 m/s. (a) How much time elapses before the b
daser333 [38]

Answer:

<h2>a) Time elapsed before the bullet hits the ground is 0.553 seconds.</h2><h2>b) The bullet travels horizontally 110.6 m</h2>

Explanation:

a)  Consider the vertical motion of bullet

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 9.81 m/s²  

        Displacement, s = 1.5 m      

     Substituting

                      s = ut + 0.5 at²

                      1.5 = 0 x t + 0.5 x 9.81 xt²

                      t = 0.553 s

      Time elapsed before the bullet hits the ground is 0.553 seconds.

b) Consider the horizontal motion of bullet

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 200 m/s

        Acceleration, a = 0 m/s²  

        Time, t = 0.553 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 200 x 0.553 + 0.5 x 0 x 0.553²

                      s = 110.6 m

      The bullet travels horizontally 110.6 m

6 0
3 years ago
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