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Lady_Fox [76]
3 years ago
11

The temperature of a body is from 200 to 300C.The change of temp at absolute scale is

Physics
2 answers:
Oliga [24]3 years ago
7 0

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

noname [10]3 years ago
5 0

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

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Why are sunlight and gravity not considered matter?
Nady [450]

Sunlight and gravity are not considered matter because sunlight does not have  a rest mass that is characteristic of matter while gravity is just a vector component of matter.

<u>Explanation:</u>

Sunlight has energy and momentum that makes it similar to matter but it cannot be considered matter when you consider all the factors that are characteristic of matter. Light is an electromagnetic wave that is made up of photons and  the protons do not have rest mass.

Gravity is  a vector component of matter that has both magnitude as well as direction and the gravity increases with increase in mass of an object.

6 0
3 years ago
Read 2 more answers
Someone please help!
NISA [10]
Do you know what's this unit called? it may help figure out how to do it.
8 0
3 years ago
A person takes a trip, driving with a constant speed of 89.5 km/h, except for a 22.0-min rest stop. If the person’s average spee
DanielleElmas [232]

Answer:

(a): It spends on the trip 2.75 hr (2 hours 45 minutes)

(b):  The person travels 213.9 km.

Explanation:

Vp= 77.8 km/h

V1= 89.5 km/h

V2= 0 km/h

t2= 0.36hr

t1= ?

Vp= (V1*t1 + V2*t2) / (t1 + t2)

clearing t1:

t1= 2.39 hr

Trip time= t1+t2

Trip time= 2.75 hr (a)

Distance traveled= V1*t1

Distace traveled= 213.9 km (b)

7 0
3 years ago
En un experimento de calorimetría, 0.50 kg de un metal a 100°C se añaden a 0.50 kg de agua a 20°C en un vaso de calorímetro de a
Maru [420]

Answer:

c=0.14J/gC

Explanation:

A.

2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.

B.

We can use the expression for heat transmission

Q=mc(T_2-T_1)

In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say

Q_1=-Q_2

for water we have to

c = 4.18J / g ° C

replacing we have

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

I hope this is useful for you

A.

2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.

B.

Podemos usar la expresión para la transmisión de calor

Q=mc(T_2-T_1)

En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir

Q_1=-Q_2

para el agua tenemos que

c=4.18J/g°C

reemplazando tenemos

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

7 0
3 years ago
A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.6 A runs through the wire
lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F_{mg}^> | = I(B^> × L^> )

given that

I = 2.6 A

B^> = 0.17

L^> = 0.52

so we substitute

|F_{mg}^> | = 2.6( 0.17i" × 0.52j" )

|F_{mg}^> | = 0.2298 N

Therefore, the magnitude of the magnetic force on the wire is 0.2298 N

4 0
3 years ago
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