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sdas [7]
1 year ago
11

2C6H6 + 1502 →12CO2 + 6H20

Chemistry
1 answer:
solmaris [256]1 year ago
5 0

Answer:

.926 moles

Explanation:

Rounding :

H2 0 = 18 gm/mole

   50 gm would then be   50 / 18 = 2.7777 moles of water

every two moles of 2 C6H6   produces   6 moles of water

   2.7777/6  * 2 = .926 moles

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In the late 1400s,ties among people of the same formed the basics of most aspects of life in rural west Africa
lara31 [8.8K]
Can u write it more specifically? so that I can answer
6 0
3 years ago
What happens when an ecosystem reaches the maximum number of individuals it can support
tangare [24]

Answer:

A collapse of the population is rotting, food is not enough and livelihoods have become unfeasible to decrease the number of individuals again.

Another way is to generate mutations to generate a species more vulnerable to decreasing numbers.

In this way the overpopulation is controlled.

Explanation:

In ecosystems, if an increased population breaks the balance of this and begins a new constant adaptation of the extinction of some and overpopulation of others, which may be some chains break or remain unstable.

6 0
2 years ago
Interstellar space has an average temperature of about 10 K , and an average density of hydrogen atoms of about one hydrogen ato
Bas_tet [7]

Answer:

2.2508\times 10^{19} m meter the mean free path of hydrogen atoms in interstellar space.Explanation:

The mean free path equation is given as:

\lambda =\frac{1}{\sqrt{2}\pi d^2 n}

Where"

d = diameter of hydrogen atom in meters

n =  number of molecules per unit volume

We are given: d = 100 pm = 100\times 10^{-12}= 10^{-10} m

n = 1 m^{-3}

\lambda =\frac{1}{\sqrt{2}\pi (10^{-10} m)^2\times 1 m^{-3}}

\lambda =2.2508\times 10^{19} m

2.2508\times 10^{19} m meter the mean free path of hydrogen atoms in interstellar space.

7 0
3 years ago
Predict what will be observed in each experiment below. experiment predicted observation.
irga5000 [103]

Answer:

The correct answer is -

1.  a) The bubbles will shrink, some may vanish.

2. a) Can A will make a louder and stronger fizz than can B.

Explanation:

In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.

Thus, the correct answer would be - The bubbles will shrink, some may vanish

In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.

thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.

8 0
2 years ago
How many grams are 3.01 × 1023 molecules of CuSO4?
zvonat [6]
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
4 0
3 years ago
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