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2 years ago

2C6H6 + 1502 →12CO2 + 6H20

Chemistry

1 answer:

solmaris [256]2 years ago

5 0

Answer:

.926 moles

Explanation:

Rounding :

H2 0 = 18 gm/mole

50 gm would then be 50 / 18 = 2.7777 moles of water

every two moles of 2 C6H6 produces 6 moles of water

2.7777/6 * 2 = .926 moles

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Help please !!!

docker41 [41]

Increase the force they are using to move the box by adding more helpers

Explanation:
If you want to increase the speed that the box is moving, increasing the friction would make it more difficult, decreasing the force they are using would just make it slower and increasing the angle of the ramp would make it harder. Adding more people would make it easier. “The more the merrier”

3 0

3 years ago

What is the [OH-] of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 m

velikii [3]

Answer: The $[OH^-]$ of a solution is $10^{-12}$ M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $HCl$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0912g}{36.5g/mol}=0.0025mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.0025\times 1000}{250}=0.01$

pH or pOH is the measure of acidity or alkalinity of a solution.

$HCl\rightarrow H^++Cl^{-}$

According to stoichiometry,

1 mole of $HCl$ gives 1 mole of $H^+$

Thus $0.01$ moles of $HCl$ gives = $\frac{1}{1}\times 0.01=0.01$ moles of $H^+$

Putting in the values:

$[H^+][OH^-]=10^{-14}$

$[0.01][OH^-]=10^{-14}$

$[OH^-]=10^{-12}$

Thus the $[OH^-]$ of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution is $10^{-12}$ M

8 0

4 years ago

Balance the equation with the correct coefficients.

Dmitry [639]

Explanation:

In general, to balance an equation, here are the things we need to do:

Count the atoms of each element in the reactants and the products.

Use coefficients; place them in front of the compounds as needed.

7 0

3 years ago

What type of bond exists between the atoms in a molecule of N2?

Dvinal [7]

Answer:

Explanation:

8 0

3 years ago

Read 2 more answers

What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum

klio [65]

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

3 0

3 years ago