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SIZIF [17.4K]
2 years ago
9

2Ag (s) + H2S(s) → Ag2S(s) + H2(g)

Chemistry
1 answer:
Advocard [28]2 years ago
8 0

Answer: Oxidation half: 2Ag\rightarrow 2Ag^++2e^-

Reduction half: 2H^++2e^-\rightarrow H_2

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

2Ag(s)+H_2S(s)\rightarrow Ag_2S(s)+H_2(g)

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Oxidation half: 2Ag\rightarrow 2Ag^++2e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Reduction half: 2H^++2e^-\rightarrow H_2

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The combustion of 3.795 mg of liquid B, which contains only C, H, and O, with excess oxygen gave 9.708 mg of CO2 and 3.969 mg of
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Answer:

Explanation:

9.708 mg of CO₂ will contain 12 x 9.708 / 44 = 2.64 g of C .

3.969 mg of H₂O will contain 2 x 3.969 / 18 = .441 g of H .

mg of O in given liquid B = 3.795 - ( 2.64 + .441 ) = .714 mg

ratio of mg of C , H , O in the compound = 2.64 : .441 : .714

ratio of no of atoms  of C , H , O in the compound

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= .22 / .22 : .44 / .22 : .044 / .22

= 1 : 2 : .2

1 x 5 : 2 x 5 : .2 x 5

= 5 : 10 : 1

empirical formula of the compound = C₅H₁₀O

Volume of 89.8 mL at 1 .00 atm at 200⁰C

volume of gas at 1 atm and 0⁰C = 89.8 x 273 / 473 mL

= 51.83 mL

51.83 mL weighs .205 g

22400 mL will weigh .205 x 22400 / 51.83 g

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86 n = 88.6

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So molecular formula is same as empirical formula

C₅H₁₀O is molecular formula .

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