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kotykmax [81]
2 years ago
10

Which is heavier, 1 m3 of steel or 1 m3 of aluminium?​

Physics
1 answer:
Strike441 [17]2 years ago
5 0

Answer:

Steel is almost 2.9 times heavier the aluminium.

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An uncharged 30.0-µF capacitor is connected in series with a 25.0-Ω resistor, a DC battery, and an open switch. The battery has
kolezko [41]

Answer:

(a) Maximum current through resistor is 1.43 A

(b) Maximum charge capacitor receives is 1.50\times 10^{-3}\text{ C}.

Explanation:

(a)

In an RC (resistor-capacitor) DC circuit, when charging, the current at any time, <em>t</em>, is given by

I(t) = I_0e^{-t/\tau}

Here, I_0 is the maximum current and <em>τ</em> represents time constant which is given by RC (the product of the resistance and capacitance).

The maximum current is given by

I = \dfrac{V}{R_\text{eff}}

<em>V</em> is the emf of the battery and R_\text{eff} is the effective resistance.

In this question, R_\text{eff} = 10.0 Ω + 25.0 Ω = 35.0 Ω

I = \dfrac{50.0\text{ V}}{35.0\ \Omega} = 1.43\text{ A}

(b) The maximum charge is given

<em>Q</em> = <em>CV</em>

where <em>C</em> is the capacitance of the capacitor

Q = (30.0\times10^{-6}\text{ F})(50.0\text{ V}) = 1.50\times 10^{-3}\text{ C}

3 0
3 years ago
Read 2 more answers
Is it possible for an atom to have an electric charge?
jeka57 [31]
False an atom can not have an electric charge.
7 0
3 years ago
5. A student travels 11 m north and then turns around to travel 25 m south. If the total time of travel is 12 sec., find a) The
11111nata11111 [884]

Explanation:

Given that,

A student travels 11 m north and then turns around to travel 25 m south.

Total time, t = 12 s

The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m

Displacement of the student or the shortest path covered is d = 25-11 = 14 m

(a) The student's average speed = total distance/total time

s=\dfrac{36\ m}{12\ s}\\\\s=3\ m/s

(b) The student's average velocity = total displacement/total time

v=\dfrac{14\ m}{12\ s}\\\\v=1.17\ m/s

4 0
3 years ago
An electric drill
Lera25 [3.4K]

Answer:

Incomplete question. Complete question is: An electric drill starts from rest and rotates with a constant angular acceleration. After the drill has rotated through a certain angle, the magnitude of the centripetal acceleration of a point on the drill is twice the magnitude of the tangential acceleration. Determine the angle through which the drill rotates by this point.

The answer is :  Δ θ = 1 rad

Explanation:

Ok, so the condition involves the centripetal acceleration and the tangential acceleration, so let’s start by writing expressions for each:

Ac= centripetal acceleration            At= tangential acceleration

Ac = V² / r                                                At = r α  

Because we have to determine the angle ultimately, therefore we should convert the linear velocity into angular velocity in the expression for centripetal acceleration

V = r ω

Ac = (r ω)² / r = r² ω² / r

Ac = r ω²

now that we have expressions for the centripetal and tangential acceleration, we can write an equation that expresses the condition given: The magnitude of the centripetal acceleration is twice the magnitude of the tangential acceleration.

Ac = 2 At

That is,  

r ω² = 2 r α

it is equivalent to;

ω²  = 2 α

now we have the relation between angular speed and angular acceleration, but we also need to determine the angular displacement as well. Therefore choose a kinematics equation that doesn’t involve time because time is not mentioned in the question. Thus,  

ω² – ω°² = 2 α Δ θ

such that ω° = 0

and ω² = 2 α

therefore;

2 α - 0 = 2 α Δ θ

2 α = 2 α Δ θ

So the angle will be :  Δ θ = 1 rad

7 0
3 years ago
You are 2.4 from a plane mirror, and you would like to take a picture of yourself in the mirror. You need to manually adjust the
Wittaler [7]

Answer:

option (D)

Explanation:

your distance from the plane mirror = 2.4 m

According to the property of the plane mirror, the distance between the object and the mirror is equal to the distance between the image and the mirror.

So, the distance  between you and your image is two times the distance between you and mirror.

the distance between you and your image = 2 x 2.4 = 4.8 m

5 0
3 years ago
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